Make hours to seconds to match meters
19.6*3600=70560 seconds
And is dropped from a height of 15.4 meters then the velocity will be
15.4m/70560s = 0.0002182539m/s
Answer:
I think its a,c,d,f, and g
Answer:
7.2 years
Step-by-step explanation:
![f(t) =200(1 - 0.956e^{-0.18t})](https://tex.z-dn.net/?f=f%28t%29%20%3D200%281%20-%200.956e%5E%7B-0.18t%7D%29)
where f(t) is the length and t is the number of years old
given the Mike measures 148 cm, we need to find out the age
So we plug in 148 for f(t) and solve for t
![148 =200(1 - 0.956e^{-0.18t})](https://tex.z-dn.net/?f=148%20%3D200%281%20-%200.956e%5E%7B-0.18t%7D%29)
divide both sides by 200
![\frac{148}{200} = 1 - 0.956e^{-0.18t}](https://tex.z-dn.net/?f=%5Cfrac%7B148%7D%7B200%7D%20%3D%201%20-%200.956e%5E%7B-0.18t%7D)
Now subtract 1 from both sides
![-0.26= - 0.956e^{-0.18t}](https://tex.z-dn.net/?f=-0.26%3D%20-%200.956e%5E%7B-0.18t%7D)
Divide both sides by -0.956
![\frac{0.26}{0.956} =e^{-0.18t}](https://tex.z-dn.net/?f=%5Cfrac%7B0.26%7D%7B0.956%7D%20%3De%5E%7B-0.18t%7D)
Now take ln on both sides
![\frac{0.26}{0.956} =e^{-0.18t}](https://tex.z-dn.net/?f=%5Cfrac%7B0.26%7D%7B0.956%7D%20%3De%5E%7B-0.18t%7D)
![ln(\frac{0.26}{0.956} )=-0.18tln(e)](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B0.26%7D%7B0.956%7D%20%29%3D-0.18tln%28e%29)
![ln(\frac{0.26}{0.956} )=-0.18t](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B0.26%7D%7B0.956%7D%20%29%3D-0.18t)
divide both sides by -0.18
t=7.2
So 7.2 years