Question

A rope pulling a sled is sloped at 15° upward at the point of contact. The tension in the rope is 50.0 N. What is the horizontal component of the force?
A.13N
B.48N
C.50 N
D.2.0 N

Answer 1

Answer:

The horizontal component of the force is 48 N.

Step-by-step explanation:

The angle that the rope makes with with the horizontal is 15°, that means, the horizontal component of the force $F_H$ is

$cos(15^o)=\frac{F_H}{50N}$

$\boxed{ F_H=50N*cos(15^o)=48N}$