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3 years ago

A= 12b1+b2h ; solve for b1

Mathematics

1 answer:

slega [8]3 years ago

8 0

Answer:

b1 = 0, b2 = 0

EXPLICACION

A = 12 b1 + b2 h

A - 12 b1 - b2 h = 0

b2!=0, h = -(12 b1)/b2

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Which of the following correctly describes the domain of the function shown

labwork [276]

Option D:

$\{x: x \neq 1\}$ is the domain of the function.

Solution:

Given function is

$$r(x)=\frac{2 x}{x-1}$

<u>To find the domain of the function:</u>

Option A: $\{x: x \neq 0\}$

Substitute x = 0 in r(x).

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If x = 0, then r(0) = 0

So that x ≠ 0 is false.

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Option B: $\{x: x \neq \pm 1\}$

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If x = –1, then r(–1) = 1

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So, $\{x: x \neq \pm 1\}$ is not the domain of the function.

Option C: $\{x: \text { all real numbers }\}$

Substitute x = 1 in r(x).

$$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}$

It is indeterminate.

So, all real numbers are not the domain of the function.

Option D: $\{x: x \neq 1\}$

Substitute x = 1 in r(x).

$$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}$

It is indeterminate.

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Can someone help me with this math homework please!

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Answer:

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Step-by-step explanation:

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