First we rewrite the functions:
y = 2x
y = x ^ 10
We note that the second function always has values of y greater than the first function. However, there is a value of x for which the first function is greater.
For x = 1 we have:
y = 2 (1) = 2
y = (1) ^ 10 = 1
We note that:
2> 1
Answer:
Yes, the value of function y = 2x eventually exceed the value of function y = x ^ 10.
28/11.2 = 2.5
since they are similar and openly stated as parrallelograms, you know that they have a scale of the longest edge of EFGH to the longest edge of JKLM
Answer:
A is false
Step-by-step explanation:
notice how in both diagrams, there are 4 triangles with lengths a, b, c, but in each diagram the triangles are just rotated and positioned differently. if there are the same amount of triangles in both diagrams, and the have equal lengths then the area of the remaining figure, should both match up.
basically the area of the big square in Step 2, is equal to both of the shaded squares, combined area, in Step 1.
