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Damm [24]
3 years ago
11

Universal containers has two teams: Sales and Services. Both teams interact with the same records. Sales users use ten fields on

the Account Record. Services users use three of the same fields as the Sales team, but also have five of their own, which the sales team does not use .What is the minimum configuration necessary to meet this requirement?
Computers and Technology
1 answer:
Oxana [17]3 years ago
6 0

Answer:

Two profiles, one record type, two page layouts.

Explanation:

Record types and functions allow you to present forward different business processes, pick-list values, as well as page layouts to diverse range of users based on their profiles.

Going by the question, we can conclude that the minimum necessary configuration in order to meet the requirement in the question above are:Two profiles, one record type, two page layouts.

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Consider the following code segment: theSum = 0.0 while True: number = input("Enter a number: ") if number == ": break theSum +=
Strike441 [17]

n where n is the number of chances user takes to enter a blank number and n>=1.

<u>Explanation:</u>

The loop starts with a universal condition where it is initialized using a true value. Hence the iteration count goes to 1. The user is asked to enter a number after 1st iteration. If number is a blank number, the loop is terminated, else the loop goes on until the users enters a blank number. Hence the iterations depend on the number of chances taken by the user to enter a blank number. Since the user is going to enter a number at least once, the minimum value of n will be 1.

4 0
3 years ago
Assuming that the actual process ids of the parent and child process are 2600 and 2650 respectively, what will be printed out at
VashaNatasha [74]

Answer:

Output explanation to the given code can be defined as follows:

Explanation:

In A the output is 0 , It will return fork value of the child process that is 0. so, 0 is printed during child process.  

In B the output is 2650 , in which the getpid() method returns the child process id  value that is 2650.  

In C the output is 140, As it is declared in key, all process have their own "value" copies. 20 are inserted during childhood, so 140 are written.  

In D the output is 2650, its fork() method returns the child ID to the parent process. so the value 2650 is printed.  

In E the output is 2600, Its getpid() method will returns parent process id  that is equal to 2600.  

In F the output is 120 Since the value is declared in primary, all process so their own "value" copies. 120 will be printed during process.

4 0
3 years ago
The intention of this problem is to analyze a user input word, and display the letter that it starts with (book → B).
yulyashka [42]

Answer:

Here is the C++ program:

#include<iostream>  // to use input output functions

using namespace std;     //to identify objects like cin cout

void StartChar(string str)  {  // function that takes a word string as parameter and returns the first letter of that word in capital

   int i;  

   char c;

   do  //start of do while loop

   {

   for (int i = 0; i < str.length(); i++) {  //iterates through each character of the word str

       if(str.length()>25){  //checks if the length of input word is greater than 25

           cout<<"limit exceeded"; }  //displays this message if a word is more than 25 characters long

      c = str.at(i);   // returns the character at position i

       if (! ( ( c >= 'a' && c <= 'z' ) || ( c >= 'A' && c <= 'Z' ) ) ) {  //checks if the input word is contains characters other than the alphabet

            cout<<str<<" is not a word!"<<endl; break;}  //displays this message if user enters characters other than the alphabet

        if (i == 0) {  //check the first character of the input word

           str[i]=toupper(str[i]);  //converts the first character of the input word to uppercase

           cout<<str<<" starts with letter "<<str[i]<<endl;  }  // prints the letter that the word starts with in capital letter

   }   cout<<"Enter a word: ";  //prompts user to enter a word

      cin>>str;   //reads input word from user

}while(str!="#");   }    //keeps prompting user to enter a word until the user enters #

int main()   //start of the main() function body

{ string str;  //declares a variable to hold a word

cout<<"Enter a word: "; //prompts user to enter a word

cin>>str; //reads input word from user

   StartChar(str); }  //calls function passing the word to it

     

Explanation:

The program prompts the user to enter a word and then calls StartChar(str) method by passing the word to the function.

The function StartChar() takes that word string as argument.

do while loop starts. The for loop inside do while loop iterates through each character of the word string.

First if condition checks if the length of the input word is greater than 25 using length() method which returns the length of the str. For example user inputs "aaaaaaaaaaaaaaaaaaaaaaaaaaa". Then the message limit exceeded is printed on the screen if this if condition evaluates to true.

second if condition checks if the user enters anything except the alphabet character to form a  word. For example user $500. If this condition evaluates to true then the message $500 is not a word! is printed on the screen.

Third if condition checks if the first character of input word, convert that character to capital using toupper() method and prints the first letter of the str word in capital. For example if input word is "Computer" then this prints the message: Computer starts with the letter C in the output screen.

The program keeps prompting the user to enter the word until the user enters a hash # to end the program.

The output of the program is attached.

3 0
3 years ago
Write a function PrintShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, pr
Finger [1]

Answer:

public static void PrintShampooInstructions(int numberOfCycles){

       if (numberOfCycles<1){

           System.out.println("Too Few");

       }

       else if(numberOfCycles>4){

           System.out.println("Too many");

       }

       else

           for(int i = 1; i<=numberOfCycles; i++){

               System.out.println(i +": Lather and rinse");

           }

       System.out.println("Done");

   }

Explanation:

I have used Java Programming language to solve this

Use if...elseif and else statement to determine and print "Too Few" or "Too Many".

If within range use a for loop to print the number of times

8 0
3 years ago
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