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netineya [11]
3 years ago
13

Clare went to a concession stand that sells pretzels for $3.25, drinks for $1.85, and bags of popcorn for $0.99 each. She bought

at least one of each item and spent no more than $10. Could Clare have purchased 2 pretzels, 2 drinks, and 2 bags of popcorn? Explain your reasoning. Check your work with the video when you are ready
Mathematics
1 answer:
djyliett [7]3 years ago
7 0

Answer:

No.

Step-by-step explanation:

Price of each pretzel = $3.25

Price of each drink = $1.85

Price of each bag of popcorn = $0.99

Maximum money to be spent = $10

Price of two pretzels = $3.25 \times 2 = $6.5

Price of two drink = $1.85 \times 2 = $3.70

Price of two bags of popcorn = $0.99 \times 2 = $1.98

Total money spent for buying two items of each type = $6.5 + $3.70 + $1.98 = $12.18

The money spent when 2 pretzels, 2 drinks and 2 bags of popcorn are bought is $12.18.

But maximum money available is $10.

Therefore, Clare would not be able to buy 2 pretzels, 2 drinks and 2 bags of popcorn with the amount of money available.

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This question is incomplete; here is the complete question and find the figure attached.

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