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netineya [11]
3 years ago
13

Clare went to a concession stand that sells pretzels for $3.25, drinks for $1.85, and bags of popcorn for $0.99 each. She bought

at least one of each item and spent no more than $10. Could Clare have purchased 2 pretzels, 2 drinks, and 2 bags of popcorn? Explain your reasoning. Check your work with the video when you are ready
Mathematics
1 answer:
djyliett [7]3 years ago
7 0

Answer:

No.

Step-by-step explanation:

Price of each pretzel = $3.25

Price of each drink = $1.85

Price of each bag of popcorn = $0.99

Maximum money to be spent = $10

Price of two pretzels = $3.25 \times 2 = $6.5

Price of two drink = $1.85 \times 2 = $3.70

Price of two bags of popcorn = $0.99 \times 2 = $1.98

Total money spent for buying two items of each type = $6.5 + $3.70 + $1.98 = $12.18

The money spent when 2 pretzels, 2 drinks and 2 bags of popcorn are bought is $12.18.

But maximum money available is $10.

Therefore, Clare would not be able to buy 2 pretzels, 2 drinks and 2 bags of popcorn with the amount of money available.

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A sequence is constructed according to the following rule: its first term is 7, and each next term is one more than the sum of t
Iteru [2.4K]

Answer:

5

Step-by-step explanation:

According to the described rule, we have

a_1=7\\ \\a_1^2=7^2=49\Rightarrow a_2=4+9+1=14\\ \\a_2^2=14^2=196\Rightarrow a_3=1+9+6+1=17\\ \\a_3^2=17^2=289\Rightarrow a_4=2+8+9+1=20\\ \\a_4^2=20^2=400\Rightarrow a_5=4+0+0+1=5\\ \\a_5^2=5^2=25\Rightarrow a_6=2+5+1=8\\ \\a_6^2=8^2=64\Rightarrow a_7=6+4+1=11\\ \\a_7^2=11^2=121\Rightarrow a_8=1+2+1+1=5\\ \\\text{and so on...}

We can see the pattern

a_5=a_8=a_{11}=a_{14}=...=5\\ \\a_6=a_9=a_{12}=a_{15}=...=8\\ \\a_7=a_{10}=a_{13}=a_{16}=...=11

In other words, for all k\ge 2

a_{3k-1}=5\\ \\a_{3k}=8\\ \\a_{3k+1}=11

Now,

a_{2018}=a_{3\cdot 673-1}=5

7 0
4 years ago
Please help ( if you can then please help with <br> both questions )
tatuchka [14]

Answer:

For number 1, -1.125 and -9/8. For number 2, -46.

Step-by-step explanation:

6 0
3 years ago
Match each output to its input for the function. Let f(x) = −2x + 3 f(0) f(−32) f(10) f(−17) and the choices are 3,-17,37,6
Andru [333]

Answer:

Below

Step-by-step explanation:

● f(x) = -2x + 3

● f (0) = -2 (0) +3 = 3

● f(-32) = -2(-32)+3 = 64 + 3 = 67

● f(10) = -2(10) +3 = -20 + 3 = -17

● f(-17) = -2(-17) + 3 = 34 + 3 = 37

● f(10) => -17

● f(-17) => 37

4 0
3 years ago
A cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shif
omeli [17]

We have been given that a cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shift is 9 units down, and the period of the function is \frac{7\pi}{12}. The graph of the function does not show a phase shift. We are asked to write the equation of our function.

We know that general form a cosine function is y=A\cos(b(x-c))-d, where,

A = Amplitude,

\frac{2\pi}{b} = Period,

c = Horizontal shift,

d = Vertical shift.    

The equation of parent cosine function is y=\cos(x). Since function is reflected about x-axis, so our function will be y=-\cos(x).

Let us find the value of b.

\frac{2\pi}{b}=\frac{7\pi}{12}

7\pi\cdot b=24\pi

\frac{7\pi\cdot b}{7\pi}=\frac{24\pi}{7\pi}

b=\frac{24}{7}

Upon substituting our given values in general cosine function, we will get:

f(x)=-11\cos(\frac{24}{7}x)-9

Therefore, our required function would be f(x)=-11\cos(\frac{24}{7}x)-9.

7 0
3 years ago
An English teacher has 6 short stories, 4 novels, and 23 poems to choose from. How many ways can he assign one of each to his cl
Karolina [17]

Answer:

552

Step-by-step explanation:

This is a problem of permutation which can be solved by rule of fundamental counting principle.

This principle states that if there "m" ways of doing one thing and "n" ways of doing other. Then no. of ways in which both the things can be done together is "m*n". This can be extended for m, n, p,r, s things and so on.

example: if there are 5 shirts and 3 trousers then number of ways in which the shirts and trousers can be worn is 5*3 = 15 ways.

_____________________________________________

The given problem is on similar concepts.

here  6 short stories, 4 novels, and 23 poems have to be assigned to his class.

Thus it can be done in 6*4*23 = 552 ways.

5 0
3 years ago
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