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Pachacha [2.7K]
3 years ago
7

How do you solve this

Mathematics
1 answer:
Doss [256]3 years ago
6 0

Answer:y=7

Step-by-step explanation:x=2+7=8

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A mass attached to a spring is pulled toward the floor so that its height above the floor is 10 mm (millimeters). The mass is th
e-lub [12.9K]

Answer:

a) The mass is released at t = 0 when h is minimum. Half a cycle later h reaches its maximum and another half a cycle it reaches its minimum again. Hence over one cycle, h varies with t as follows:

b) According to the graph obtained in part a), h(t) could be modeled by a cosine function shifted (translated) vertically up and horizontally to the right. Hence

Step-by-step explanation:

5 0
2 years ago
Can someone help please?
Katarina [22]

Answer:

g = 6

Step-by-step explanation:

<em>To find the slope you do:</em>

m = change in y ÷ change in x or (y2 - y1) ÷ (x2 - x1)

  • x1 = 4, y1 = -7
  • x2 = g, y2 = -3
  • m (the slope) = 2

<em>Sub in the values:</em>

2 = (-3 - -7) ÷ (g - 4) - we can simplify this

2 = (4) ÷ (g - 4)

4 divided by what gives us 2? 2. This means that g - 4 = 2, g = 2 + 4 which is 6:

g = 6

Hope this helps!

8 0
3 years ago
Read 2 more answers
Help ASPP<br><br>-3/5 x = 18 <br>-30<br>-10 4/5<br>10 4/5<br>30​
kompoz [17]

Answer:

-30

Step-by-step explanation:

move and divide -3/5 to the right side

-3/5x = 18

x=18÷(-3/5)

x= -30

5 0
2 years ago
Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
2 years ago
What is the measure of Angles are not necessarily drawn to scale.
miskamm [114]
X is 58° (your welcome:)
8 0
2 years ago
Read 2 more answers
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