Answer:
a) The mass is released at t = 0 when h is minimum. Half a cycle later h reaches its maximum and another half a cycle it reaches its minimum again. Hence over one cycle, h varies with t as follows:
b) According to the graph obtained in part a), h(t) could be modeled by a cosine function shifted (translated) vertically up and horizontally to the right. Hence
Step-by-step explanation:
Answer:
g = 6
Step-by-step explanation:
<em>To find the slope you do:</em>
m = change in y ÷ change in x or (y2 - y1) ÷ (x2 - x1)
- x1 = 4, y1 = -7
- x2 = g, y2 = -3
- m (the slope) = 2
<em>Sub in the values:</em>
2 = (-3 - -7) ÷ (g - 4) - we can simplify this
2 = (4) ÷ (g - 4)
4 divided by what gives us 2? 2. This means that g - 4 = 2, g = 2 + 4 which is 6:
g = 6
Hope this helps!
Answer:
-30
Step-by-step explanation:
move and divide -3/5 to the right side
-3/5x = 18
x=18÷(-3/5)
x= -30
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
