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Novosadov [1.4K]
3 years ago
9

How do you solve the equation in detail :: 12(2w-3)=6w

Mathematics
1 answer:
Daniel [21]3 years ago
8 0
12(w-3)=6w

Distrubute the 12
12(2w)-12(3)=6w
24w-36=6w
Subract 24w from both sides
-36=6w-24w
-36=-18w
Divide both sides by -18
w=2
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What is 1/2 + 1/6, please explain, I'm very bad at math
Masja [62]

Answer:

Before adding, we need to make sure the denominators are the same. We can do so by multiplying the fraction by a common multiple. In this case, 3 is a multiple of 6, so we can change 1/2 to 3/6. 3/6 is still equal to 1/2, so nothing changes.

Now we have 3/6+1/6, which is 4/6 (add the numerator).

4/6 can be simplified to 2/3 and 2 is a multiple of 4 and 6.

So, therefore, the answer is 2/3.

4 0
3 years ago
A jewelry store is featuring a diamond in the shape of a square pyramid. The side length of
BARSIC [14]

Answer:

128√5/3 mm³

Step-by-step explanation:

Since we are not told what to find, we can as well look for the volume of the pyramid

Volume of a square pyramid: V = (1/3)a²h

a is the side length of the square

h is the height of the pyramid

Given

a = 8mm

l² = (a/2)² + h²

l² = (a/2)² + h²

6² = (8/2)² + h²

h² = 6² - 4²

h² = 36 - 16

h² = 20

h = √20

Volume of a square pyramid =  (1/3)*8²*√20

Volume of a square pyramid = 1/3 * 64 * 2√5

Volume of a square pyramid = 128√5/3 mm³

7 0
3 years ago
The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
nexus9112 [7]

Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

Therefore, E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

8 0
3 years ago
What is the value of x?
melisa1 [442]

Answer:

x=71

Step-by-step explanation:

38+x+x=180

x+x=142

2x=142

x=71

3 0
3 years ago
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