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Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1
Answer:
52/ 10 = 5 2/10 or 5 1/5
Step-by-step explanation:
first turn the mixed fractions into improper fraction
13 1/10= 131/10
7 9/10= 79/10
since the two fractions already have a common denominator just subtract
131 - 79 = 52
52/ 10 = 5 2/10 or 5 1/5
MrBillDoesMath!
Answer: The dependent variable depends on another variable for its value. For example, if y = 2x, setting x = 1 forces y= 2.; setting x = 10, forces y =20. There are no other possibilities for y once x ids chosen. So y is the dependent variable and x is the independent one. You can pick values for the independent variable (x) but no so for the dependent one.
MrB
Answer:
x=-1 hope this helpsss
Step-by-step explanation: