Find the limit of the sequence described by the general expression 5n+ (-1) n /n^2

Mathematics

1 answer:

elena-s [515]3 years ago

5 0

Answer:

b. 0

Step-by-step explanation:

The expression can be rewritten as:

$A_{n} = \frac{5\cdot n}{n^{2}} + \frac{(-1)^{n}}{n^{2}}$

As n becomes greater and begins diverging to infinity, each component of the sum converges to zero. Then, the limit of the sequence is zero.

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4 0

2 years ago

What is the answer to this

LekaFEV [45]

$4 \dfrac{3}{5} \times \dfrac{5}{12} =$

$= \dfrac{23}{5} \times \dfrac{5}{12}$

You changed the mixed numeral into a fraction correctly.
Now you need to multiply the fractions.
Multiply the numerators together, and multiply the denominators together.

$= \dfrac{23 \times 5}{5 \times 12}$

Now we could multiply out the numerator and denominator, and then we'd need to reduce the fraction, but before we multiply, we see there is a factor of 5 both in the numerator and in the denominator, so we can reduce before we multiply.

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6 0

3 years ago

Please help me solve this equation and show the work show me how you got the answer

Nesterboy [21]

Answer: k=3

Step-by-step explanation:

To solve for k, you want to isolate k.

$\frac{2}{5} (5k+35)-8=12$ [add both sides by 8]