3 years ago

('h(I) = -35(h(n) = h(n - 1)×2h(3) =

Mathematics

1 answer:

qwelly [4]3 years ago

3 0

Answer:

h(3)=n(h_3)×3that is the answer

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3 years ago

('h(I) = -35(h(n) = h(n - 1)×2h(3) =​

('h(I) = -35(h(n) = h(n - 1)×2h(3) =