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sleet_krkn [62]
3 years ago
14

1. Following are the terms of the toothpick sequence: 8, 14, 20, 26, 32.

Mathematics
1 answer:
Ratling [72]3 years ago
4 0

Answer:

6

Step-by-step explanation:

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I think u multiply and then divide by one of its multiples
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if the diagonals of a quadrilateral biscects each other, then the quadrilateral is a parallelogram. true or false
Irina-Kira [14]

Answer:

true

Step-by-step explanation:

7 0
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Help pls what's the common difference
horsena [70]

<u><em>Answer: </em></u>

#9: 5

#10: -2

#11: -1.5

<em><u>Step-by-step explanation:</u></em>

<em><u>#9:</u></em> 3,8,13,18,23,(28),(33),(38),.. <em>Go up by 5 each time, so the common difference is </em><u><em>5</em></u><em>.</em>

<u><em>#10:</em></u> 11,9,7,5,3,(1),(-1),(-3),... <em>Go down </em><em>(-)</em><em> by 2 each time, so the common difference is </em><u><em>-2</em></u><em>.</em>

<u><em>#11:</em></u> 3, 1.5, 0, -1.5, -3, (-4.5), (-6), (-7.5),... <em>Go down </em><em>(-) </em><em>by 1.5 each time, so the common difference is </em><u><em>-1.5</em></u><em>.</em>

7 0
3 years ago
In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct
kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

                  =(0.93\times0.03)+(0.10\times0.97)\\=0.1249

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

6 0
3 years ago
Yesterday 6/7 of the 63 students gave their speeches how many gave their speeches
storchak [24]
7 goes into 63 9 times so 6/7 you would take away one 9 so it would be 6 times 9 which is equal to 54

Answer: 54 students
4 0
3 years ago
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