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Anestetic [448]
2 years ago
6

Stanley has $18 to spend on packs of trading cards that cost $1.50 each. The inequality 18≥1.5p represents the number of packs p

he can buy. What is the greatest number of whole packs Stanley can buy?
Mathematics
1 answer:
V125BC [204]2 years ago
7 0

Answer:

Numbers of packs p is 12

Step-by-step explanation:

Data :

  Money  = $18

 Price of a  card = $1.5

 Equation     :    18 ≥ 1.5p

Solve the equation  for p

       18/1.5  ≥  p

     12 ≥ p

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Step-by-step explanation:

To solve this , we use the equation of finding a slope wig a line.

m = (y2 - y1)/(x2 - x1)

From the question, we know that:

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Hence,

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3 years ago
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what is the volume measured in cubic centimeters, of the box below? do not include units in your answer
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If 7 giant solar power plants generate 1.3 gigawatts (GW) of energy to power 900,000 homes, how many gigawatts can 21 giant sola
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6 0
3 years ago
manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe
Naddik [55]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32

he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64

add both amounts, and that's how much is for the whole 21 years.
6 0
3 years ago
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