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DerKrebs [107]
4 years ago
12

What is 9 1\2 + 12 11\20

Mathematics
2 answers:
katrin [286]4 years ago
6 0
9 1/2 + 12 11/10
= 19/2 + 131/10 (cuz u multiply 2 x 9 and add 1, and agaim w the other 10x12+11)
= 150/10
inn [45]4 years ago
4 0
1/2 of 11/20 is 10/20 so add that together. Then just add 9+12... sorry im not going to give answers but i hope that helps somewhat

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2x + 2= -3<br> What is the answer
Sati [7]
-5/2 is your answer :)
5 0
3 years ago
Read 2 more answers
Use the normal distribution of SAT critical reading scores for which the mean is 502 and the standard deviation is 116. Assume t
PSYCHO15rus [73]

Answer:

(a) 93.19%

(b) 267.3

Step-by-step explanation:

The population mean and standard deviation are given as 502 and 116 respectively.

Consider, <em>X</em> be the random variable that shows the SAT critical reading score is normally distributed.

(a) The percent of the SAT verbal scores are less than 675 can be calculated as:

P(X

Thus, the required percentage is 93.19%

(b)

The number of SAT verbal scores that are expected to be greater than 575 can be calculated as:

P(X>575)=P(\frac{x-502}{116}>\frac{575-502}{116}\\P(X>575)=P(Z>\frac{575-502}{116})\\P(X>575)=P(Z>0.6293)\\P(X>575)=0.2673

So,

Out of 1000 randomly selected SAT verbal scores, 1000(0.2673) = 267.3 are expected to have greater than 575.

8 0
3 years ago
ratio 7;2 if the books is 450 pages long how many pages will be devoted to core concept and how many pages will be devoted to ad
maxonik [38]
7:2 is pages to advanced programing?

8 0
3 years ago
Consider the following binomial experiment:
Sedbober [7]

Answer:

0.624

Step-by-step explanation:

Given that:

Number of copiers with the company = 4

It is a binomial experiment.

Probability that on a given day, one copier will break down = \frac{23}{50}

p = \frac{23}{50} = 0.46

q = 1-p = 1-\frac{23}{50}= \frac{27}{50} = 0.54

<em>Formula for Binomial probability: </em>

P(x=r) = _{n}C_{r}p^rq^{n-r}

We have to find P(x >= 2)

P(x >= 2) = P(X=2)+P(X=3)+P(X=4)

P(x=2) = _{4}C_{2}0.46^2\times 0.54^{2} = 0.37\\P(x=3) = _{4}C_{3}0.46^3\times 0.54 = 0.21\\P(x=4) = _{4}C_{4}0.46^4\times 0.54^{0} = 0.044

P(x >= 2) = 0.37 + 0.21 + 0.044 = \bold{0.624}

4 0
3 years ago
#59<br> Does the limit of f(x) as x approaches 3=does not exist
8090 [49]
Plug x = 3 into the first piece to get
2(x+1) = 2*(3+1) = 2*4 = 8

Do the same for the last piece
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So as we approach x = 3 from either the left or right side, the limiting value is 8

The final answer is 8

4 0
3 years ago
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