A = (1/2) b * h
h = b - 5
42 = (1/2) * b * (b - 5)
42 = (1/2) * b^2 - 5b
multiply both sides by 2 to clear the fraction (1/2)
2(42) = 2(1/2) *b^2 - 5b
84 = b^2 -5b
Since this is a quadratic equation, subtract 84 from both sides so that it is set = to zero.
b^2 - 5b - 84 = 0
Now factor.
(b - 12)(b + 5) = 0
b - 12 = 0; b = 12
b + 5 = 0; b = -5
You can't have a negative length so the answer is 12m
To check the answer:
A = (1/2) * 12* 7
A = 42 m^2
Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer:
1/2 - 3(1/2 + 1)²
simplify the expression (1/2 + 1)
1/2 - 3•(3/2)²
using PEMDAS, we see we have to evaluate the exponent first
(3/2)² = 9/4
rewrite the equation
1/2 - 3 • (9/4)
multiply 3 by (9/4)
1/2 - (27/4)
subtract
-25/4
(1 + 1/3)² - 2/9
simplify the expression (1 + 1/3)
(4/3)² - 2/9
using PEMDAS, we see we have to evaluate the exponent first
(4/3)² = 16/9
rewrite the equation
(16/9) - (2/9)
subtract
14/9
Answer:
x = -2
y=-3
(-2,-3)
Step-by-step explanation:
Both equations are equal to y
We can set them equal to each other
y = 3x + 3
y = x − 1
3x+3 = x-1
Subtract x from each side
3x+3 -x = x-1-x
2x+3 = -1
Subtract 3 from each side
2x+3-3 = -1-3
2x = -4
Divide each side by 2
2x/2 = -4/2
x = -2
Now we need to find y
y = x-1
y = -2-1
y = -3
y = x-1
