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8_murik_8 [283]
3 years ago
11

Hayden is 59 inches tall and is standing on top of a ladder that is 2 yards y’all in inches what is the distance from the top of

Hayden’s head to the ground
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

131 inches

Step-by-step explanation:

1 yard = 36 inches

36 x 2 = 72

72 + 59 = 131

c:

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Find the area of a triangle bounded by the y-axis, the line
Pepsi [2]
The area is 68.47.

A drawing of the triangle is attached.

We first plot the y-intercept of the line given to us, f(x)=34-4x.  This is in the form f(x)=mx+b, so the y-intercept, b, is 34.  

Next we use the slope to find the next points of the line.  The slope is -4, which can be written as -4/1 (rise/run).  This means from the y-intercept, we go down 4 and over 1 to plot the next point, and continue in this manner.  We now have the y-axis and this line drawn.

Next we use the slope of the line to find the slope of the perpendicular line described.  Two lines are perpendicular if their slopes are negative reciprocals of each other.  The slope of the first line was -4/1; this means the slope of this line must be 1/4.  We also know this point goes through the origin, so 0 is the y-intercept, and we have the equation f(x)=1/4x+0.

To graph this, plot a point at 0, the y-intercept.  The slope is 1/4, so we go up 1 and over 4 to the next point.  This happens to be on the line we previously drew.

To find the area of this triangle, we need to identify the base and height.  The height will be perpendicular to the base.  The two sides that form a right angle are the bottom and the right hand side, so the bottom is the base and the right hand side is the height.

Now we find the length of each of these sides using the distance formula.  For the height:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(34-1)^2+(0-4)^2}
\\
\\=\sqrt{33^2+(-4)^2}=\sqrt{1089+16}=\sqrt{1105}\approx33.24

To find the length of the base:
d=\sqrt{(0-1)^2+(0-4)^2}=\sqrt{(-1)^2+(-4)^2}=\sqrt{1+16}=\sqrt{17}
\\
\\\approx4.12

The area of a triangle is given by A=1/2bh:
A=1/2(33.24)(4.12) = 68.4744 ≈ 68.47

5 0
3 years ago
Match the function in the left column with its period in the right column.
kiruha [24]

The results for the matching between function and its period are:

  • Option 1 - Letter D
  • Option 2 - Letter A
  • Option 3 - Letter C
  • Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi

Thus, the option 1 matches with the letter D.

2) Option 2

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}

Thus, the option 2 matches with the letter A.

3) Option 3

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{2} =\pi

Thus, the option 3 matches with the letter C.

4) Option 4

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{8} =\frac{\pi }{4}

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

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Step-by-step explanation:

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