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3 years ago

. How many servings are there in 22.5 ounces of trail mix?

Mathematics

2 answers:

olga_2 [115]3 years ago

5 0

Answer:

9 ounces

Step-by-step explanation:

Basile [38]3 years ago

4 0

Answer: 11.5 ......................

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19(-16)<br> helpppppppppppppppp

Anna71 [15]

The answer to your question is -304

8 0

4 years ago

Simplify 4a + 8b - 6b + 2a

Deffense [45]

Here is your answer: Combine like terms: 4a+2a=6a and 8b-6b=2b Your answer is 6a+2b

8 0

3 years ago

A container is filled with 100 grams of bird feed that is 80% seed. Tom and Sally want to mix the 100 grams with bird feed that

marta [7]

Answer:

Initially, we had:

100 grams of a mixture that is 80% seed, (or 0.8 in decimal form)

This means that the quotient between the mass of seeds and the total mass of the mixture is equal to 0.8

Then the mass of seeds, x, can be calculated as:

x/100g = 0.8

x = 0.8*100g

x = 80g

We also have another mixture, that is 5% seed (or 0.05 in decimal form)

This means that in X grams of this mixture, there will be y grams of seeds, such that:

y/X = 0.05

y = 0.05*X grams

Now, we want to create a mixture that is 40% seeds (or 0.4 in decimal form).

Let's do this.

If we add X grams of the 5% mixture, the total mass will be:

M = 100g + X.

The total mass of seeds will be:

m = 80g + X*0.05

and we want that the quotient between the mass of seeds and the total mass to be exactly 0.4

m/M = 0.4

(80g + X*0.05)/(100g + X) = 0.4

Let's solve this for X.

(80g + X*0.05) = 0.4*(100g + X)

80g + X*0.05 = 40g + X*0.4

80g - 40g = X*0.4 - X*0.05

40g = X*0.35

40g/0.35 = X = 114.2g

If we want the mixture to be exactly 40% seeds, we need to add 114.2g of the 5% mixture. (We already can see that Tom is closer to the exact result than Sally)

If we add 114g, like Tom wants, we will have:

M = 100g + 114g = 214g

m = 80g + 0.05*114g = 85.7g

m/M = 85.7g/214g = 0.4005

This is a really good aproximation, if we write this in percentage form this would be:

0.4005*100% = 40.05%

8 0

3 years ago

A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability

Hoochie [10]

Answer:

The probability of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

A city council consists of seven Democrats and five Republicans.
A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\times (n-k)!}$

Compute the number of ways to select four people as follows:

${12\choose 4}=\frac{12!}{4!\times (12-4)!}=495$

Compute the number of ways to selected two Democrats as follows:

${7\choose 2}=\frac{7!}{2!\times (7-2)!}=21$

Compute the number of ways to selected two Republicans as follows:

${5\choose 2}=\frac{5!}{2!\times (5-2)!}=10$

Then the probability of selecting two Democrats and two Republicans as follows:

$P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242$

Thus, the probability of selecting two Democrats and two Republicans is 0.4242.

6 0

3 years ago

zane and shelby's grandfather is 5 times as old as the total of their ages. If their grandfather is 70 and Shelby is 6, how many

wel

G=5(z+s)
70=5(z+6)
70=5z+30
40=5z
z=8

Zane is 8

7 0

3 years ago