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alisha [4.7K]
3 years ago
9

Pls help help help help help help ​

Mathematics
2 answers:
oee [108]3 years ago
8 0
-89 :)...................................................................
Sati [7]3 years ago
5 0

Answer:

-89

Step-by-step explanation:

-89

-89= 10(-7) - 19   ----------->  -70 - 19

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A 45 foot ladder is leaning against a building. If the bottom of the ladder is 27 feet from the base of the building, how tall i
taurus [48]

Answer:

The height of building to the nearest foot is h = 36 foot

Step-by-step explanation:

We have given,

Length of ladder leaning against a building, l = 45 foot

Bottom length between ladder and the building , b = 27

Now, we need to find the height of building to the nearest foot.

Let the height of building be h.

Using Pythagoras theorem,

l^{2} = b^{2} +h^{2}

Here, l = 45 , b = 27 and h =?

So,

45^{2} = 27^{2} +h^{2}

h² = 45² - 27²

h = √(45² - 27²)

h = 36

The height of building to the nearest foot is h = 36 foot

8 0
3 years ago
Read 2 more answers
Please hurry! Marking beainliest!
kumpel [21]

Answer:

the ine you have selected is right

Step-by-step explanation:

we know12 inches is 1 foot we can keep going up andsee that 24 inches is 2 and so on

4 0
3 years ago
Read 2 more answers
Find the function values
babymother [125]

Step-by-step explanation:

f(x)=3x−2  so when the variable x is replace with an actual value ( − 1 ) we get  f(−1)=3(−1)−2

=−3−2

=−5

4 0
2 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
HELP ASAP!!
Over [174]
The answer is c becuse there’s only 2 cs and 3 of the others
8 0
3 years ago
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