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Elden [556K]
3 years ago
9

The following observations have been arranged in ascending order. If the median of the data is 22, then find the value of the 6t

h observation.
12,14,16,18,x-1, x+3,30,32,35,41
Mathematics
1 answer:
erica [24]3 years ago
5 0

Answer:   24

<u>Step-by-step explanation:</u>

The median is the middle number of the set.  If the set contains an even number of terms, then the median is the average of the two middle numbers.

{12, 14, 16, 18, x-1, x+3, 30, 32, 35, 41}

Cross out the end terms to find the median: {X, X, X, X, x-1, x+3, X, X, X, X}

The median is the average of the two middle numbers (x-1 and x+3).

\dfrac{(x-1)+(x+3)}{2}=22\\\\(x-1)+(x+3)=44\\\\2x+2=44\\2x=42\\x=21


The 6th term is x+3  ⇒  21 + 3   = 24

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For the problem -4(-5)(9), will the answer be positive or negative?
Scorpion4ik [409]

Answer:

Positive

Step-by-step explanation:

-4(-5)(9)

Negative cancels out negative, so it makes a positive:

20(9)

Simplify normally to get 180 as your final answer.

8 0
3 years ago
1) What is the ratio of out-of-state fans attending the game to local fans?
arsen [322]

Answer:

b

Step-by-step explanation:

4 0
2 years ago
Fiona wrote the linear equation y = x – 5. when henry wrote his equation, they discovered that his equation had all the same sol
djverab [1.8K]
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6 0
3 years ago
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A rectangular park of length 60 m breadth 50 m encloses w volleyball court of length 18 m and breadth 10 m. Find the area of the
Zanzabum

Given

A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.

To find:

The area of the park excluding the court at the rate of Rs 110 per square meter.​

Solution:

Area of a rectangle is:

Area=length \times breadth

Area of whole park is:

A_1=60 \times 50

A_1=3000

Area of volleyball court is:

A_2=18 \times 10

A_2=180

Now, the area of the park excluding the court is:

A=A_1-A_2

A=3000-180

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4 0
3 years ago
Given the graph, find the distance of GH. Round to the nearest tenth.
lord [1]

Answer:

GH = 6.3 units

Step-by-step explanation:

Assuming that 1 box represents 1 unit, the coordinate pair of G = (-2, -3), while H = (0, 3).

Distance between G and H = d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

G(-2, -3) = (x_1, y_1)

H(0, 3) = (x_2, y_2)

GH = \sqrt{(0 - (-2))^2 + (3 - (-3))^2}

GH = \sqrt{(2)^2 + (6)^2}

GH = \sqrt{4 + 36} = \sqrt{40}

GH = 6.3 units (nearest tenth)

5 0
4 years ago
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