The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
Answer:
The answer is 12.
Step-by-step explanation:
Please mark as Brainliest, this is the right answer
Answer:
the correct graph is b for this problem
It would be 505/1000 but If you need it to be reduced it would be 101/200
First, you want to multiply 2 times 7 which is 14 then do 14 to the 4th power which is 38,416, then add that by 14 to the third power which is 2,744, so then you will get 41,160 which is your answer.
