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3 years ago

If someone can answer this, I will give you 90 points. How fast in terms of miles does the speed of light travel at?

Mathematics

2 answers:

tangare [24]3 years ago

7 0

Answer:

670,616,629mph

Step-by-step explanation:

I think this is the answer

Kazeer [188]3 years ago

7 0

Step-by-step explanation:

light light travels at a speed of 299 792 kilometres per second

0.621 mile=1km

? = 299792km

0.621×299792

186170.832 miles per second

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A model rocket is 3 inches long. The real rocket is 120 feet long.

Nana76 [90]

The units are the complete story on this question. All of the choices are over 1 so the units make the answer over one. It takes more feet than it does inches to make the scale. The correct units are 120 feet / 3 inches. That makes A and B both incorrect.

You can't get 360 by any method but multiplication. The units for multiplication would be ft*in. So D is wrong. That only leaves you with C which is the answer.

5 0

3 years ago

The graph below shows the height of a projectile t seconds after it is launched. If acceleration due to gravity is –16 ft/s2, wh

nika2105 [10]

Answer:

see attached

Step-by-step explanation:

The x-coordinate of the vertex is given by ...

x = -b/(2a)

for f(x) = ax^2 +bx +c.

We see that the vertex is at x = 1, and we are given a = -16. Then we can find "b" from ...

1 = -b/(2(-16))

32 = b

We know the y-intercept of the equation is 5 (the starting height), so the equation must be ...

h(t) = -16t^2 +32t +5 . . . . . matches the last choice

5 0

3 years ago

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miv72 [106K]

Huh explanation Judd’s

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3 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

3 years ago

Three consecutive even integers have a sum of -126. What is the smallest integer ?

SSSSS [86.1K]

Answer:

-40, - 42 and -44

Step-by-step explanation:

The fastes way here is trying. Lets pick a number, intelligently, and then work on it.

We need three even integers that sum -126. These will be all negative numbers and as they are consecutive they will be very similar (for example, -33 and -35 and -37). Thus, lets start by 1/3 of -126, which is -42:

(-42)+ (-44) + (-46) = - 132, so -42 no.

Lets go a step back: -40

(-40) + (-42) + (-44) = -126

So, the integers are -40, -42 and -44

5 0

3 years ago