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ArbitrLikvidat [17]
3 years ago
14

Suppose a certain home improvement outlet knows that the monthly demand for framing studs is 2,300 when the price is $4.77 each

but that the demand is 3,300 when the price is $4.67 each. Assuming that the demand function is linear, write its equation. Use p for price (in dollars) and q for quantity?
Mathematics
1 answer:
pogonyaev3 years ago
8 0

Answer:

p + 0.0001q = 5

Step-by-step explanation:

Data provided in the question:

When Price, p₁ = $4.77 ; Demand, q₁ = 2,300

and,

When Price, p₂ = 3,300 ; Demand, q₂ = 3,300

considering the above as the points on the line,

now, the general equation for a line is given as:

\frac{q_1-q}{p_1-p}=\frac{q_2-q_1}{p_2-p_1}

on substituting the respective values, we get

\frac{2,300-q}{4.77-p}=\frac{3,300-2,300}{4.67-4.77}

or

\frac{2,300-q}{4.77-p}=\frac{1000}{-0.1}

or

2,300 - q = -10,000(4.77 - p)

or

⇒ 2,300 - q = -47700 + 10,000p

or

⇒ 10,000p + q = 2300 + 47700

or

⇒ 10,000p + q = 50000

or

⇒ p + 0.0001q = 5

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i) We have to find the determinant of A.

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iii) We have to find the values of x and y so that AB = C.

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\begin{gathered} 3(x-2y)+(3x+6y)=3(-3)+(-3) \\ 3x-6y+3x+6y=-9-3 \\ 6x+0y=-12 \\ x=\frac{-12}{6} \\ x=-2 \end{gathered}

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iv) When we want to multiply two matrices, the required condition is that the number of columns of the matrix on the left is equal the number of rows of the matrix on the right.

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iii) x = -2 and y = 1/2.

iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.

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