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salantis [7]
3 years ago
11

What is the volume of the prism to the nearest whole unit 29 240 526 715

Mathematics
2 answers:
Dahasolnce [82]3 years ago
4 0

Answer:

Step-by-step explanation:

Volume of prism=lbh

Where l=13in.

b=11in

h=5in.

Volume of prism=13*11*5=715in^3

xxTIMURxx [149]3 years ago
4 0

Answer:

You have to find the volume of the prism right? Well first you have to use the formula to find volume in your shape:

Volume of your prism = lbh (length x base x height)

First:

l = 13in.

b = 11in

h = 5in.

So, multiply those up and the answer is the volume of prism:

13 * 11 * 5 = 715in^3

I hope this helps! Please mark me as brainliest and have a good day/night!<3

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Express the confidence interval 0.555 less than 0.777 in the form Modifying above p with caret plus or minus Upper E.
Elina [12.6K]

Complete Question

Express the confidence interval 0.555 less than p less than  0.777 in the form Modifying above p with caret plus or minus Upper E.

Answer:

The modified representation is \r p \pm  E  = 0.666 \pm  0.111

Step-by-step explanation:

From the question we are told that

    The  confidence interval interval is  0.555 <  p <  0.777

Now looking at the values that make up  the up confidence interval we see that this is a symmetric  confidence interval(This because the interval covers 95%  of the area under the normal curve which mean that the probability of a value falling outside the interval is 0.05 which is divided into two , the first half on the left -tail and the second half on the right tail  as shown on the figure in the first uploaded image(reference - Yale University ) ) which means

     Now  since the confidence interval is  symmetric , we can obtain the sample proportion as follows

             \r p  =  \frac{0.555 + 0.777}{2}

            \r p  =0.666

Generally the margin of error is mathematically represented as

            E  =  \frac{1}{2}  *  K

Where  K is the length of the confidence interval which iis mathematically represented as

           K  =  0.777 -0.555

         K  = 0.222

Hence  

          ME  =  \frac{1}{2}  *  0.222

           ME  =  0.111

So the confidence interval can now be represented as

        \r p \pm  E  = 0.666 \pm  0.111

     

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