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3 years ago

A coin was flipped 150 times. The results of the experiment are shown in the following table:

Mathematics

1 answer:

Zolol [24]3 years ago

6 0

Answer:

A it is 10% higher than the theoretical probability

Step-by-step explanation:

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"Quadrilateral ABCD underwent a sequence of transformations to give quadrilateral A′B′C′D′. Which transformations could have tak

suter [353]

The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).

Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).

Translaitng 8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.

Answer: correct choice is B.

6 0

3 years ago

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We expect to see a line for a graph of a composition of a function and it's inverse function, if the domain of each is all _____

Helen [10]

The answer would be All (A)Real Numbers

4 0

3 years ago

X:y=5:3 and x+y=56 work out the value of x-y

Vladimir79 [104]

x - y = 14

given the ratio x : y = 5 : 3

then let x = 5x and y = 3x, hence equation can be expressed as

5x + 3x = 56

8x = 56 ( divide both sides by 8 )

x = 7

Hence x = 5 × 7 = 35 and y = 3 × 7 = 21

Thus x - y = 35 - 21 = 14

6 0

3 years ago

Help please asap!! What are the units and degrees that u need to put in ?

FromTheMoon [43]

Answer:

This question is unanwserable without the "Spider Tool" If you would like to revise it i'd be happy to help

Step-by-step explanation:

But the units are degrees

8 0

3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago