I hope that this answer will help u to solve your problem. But u have tto take the importance clues only .
Answer:
Following are the program to this question:
#include <iostream>//defining header file
using namespace std;
int recurs(int x, int n)//defining a method recurs that accepts two parameter
{
if(n==0)//defining if block that checks n value
{
return 1;//return value 1
}
else//defining else block
{
return x*recurs(x,n-1);//use return keyword that retun value
}
}
int main()//defining main method
{
cout<<recurs(5,3); //use print method to call recurs method
return 0;
}
Output:
125
Explanation:
In the above-given program, the integer method "recurs" is declared which accepts, two integer variables, which are "x, n", inside the method the if conditional statement is used.
- In the if block, it checks the value of n is equal to "0" if this condition is true, it will return a value, that is 1.
- Otherwise, it will go to the else block, in this block, it will use the recursive method to print its value.
Answer:
The output of the code,
phrase = "hello mom"
phrase.upper()
Would be nothing since you didnt print out anything. How ever, the output of,
phrase = "hello mom"
print(phrase.upper())
Would be, "HELLO MOM". You can get the same output by writing this,
phrase = "hello mom"
phrase = phrase.upper()
print(phrase)
Redwood
Red cedar
Bass wood
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