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Sunny_sXe [5.5K]
3 years ago
13

Which of the following correctly declares and initializes a Scanner object that will use input from the keyboard as its data sou

rce? *
1. Scanner keyboard = new (System.in);
2. Scanner keyboard = new Scanner (keyboard);
3. Scanner = new Scanner(System.in);
4. Scanner keyboard = new Scanner (System.in);
Computers and Technology
2 answers:
zepelin [54]3 years ago
5 0
Option 4 is correct.........
Norma-Jean [14]3 years ago
5 0

Answer:

it 4

Explanation:

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I watched an ad but the im button done is no where in sight, has anyone else experienced this recently. it was fine a few days a
Maurinko [17]

Answer:

This is usually just a small glitch that happens sometimes when you are seeing an ad and wanting to skip. Simple fixes to this problem include refreshing the browser or closing the application that you are in. This also would happen to me but following this fix should help with the problem.

7 0
2 years ago
What are potential problems with using nanorobots ?
mash [69]
It can penetrate the blood-brain barrier.
5 0
3 years ago
Using Sequential Search on an array of size n, the search key is definitely present in the array. The probability of matching th
MissTica

Answer:

(11n-5) / 12 is correct answer.

Explanation:

The Probability that key will match to nth term = 1/2

The Probability that key will match to n-1th term = 1/3

As all other probabilities are equal

The Total Probability that key matches to any of 1 to n-2 index = 1 - 1/2 - 1/3 = 1/6

The Probability that key matches to any of 1 to n-2 index = (1/6) / n-2 = (1/6)* (n-2))

Let P(i) = Probability that key matches to ith index.

The Average time complexity = 22 i=1 P(i) * i

The Average time complexity = 1/(6(n-2) * ( sum of 1 to n-2 ) + (n-1) / 3 + n/2

The Average time complexity = 1/(6(n-2) * ( n-2)*(n-1) / 2 + ( n-1) / 3 + n/2

The Average time complexity = 1/6 * (n-1)/2 + (n-1)/3 + n/2

The Average time complexity = (n-1)/12 + (n-1)/3 + n/2

The Average time complexity = (n-1 + 4 * n - 4 * 1 +6 * n)/12

The Average time complexity = 11n-5 / 12

so (11n-5) / 12 is correct answer.

7 0
3 years ago
The implementation stage of the SDLC is when the system is moved into operation where it can be used. What stage PRECEDES the im
antiseptic1488 [7]

The stage that precedes the implementation stage of SDLC is <u>testing</u> and it involves checking the functionality of the system.

System design involves the process of determining an overall system architecture, which typically comprises the following:

  • Hardware.
  • End users.
  • Physical processing components.
  • Software.
  • Communication channel.

Generally, there are seven (7) main stages in the systems development life cycle (SDLC) model and these include:

1. Planning.

2. Analysis.

3. Design.

4. Development.

5. Testing.

6. Implementation.

7. Maintenance.

From the above, we can deduce that the stage which precedes the implementation stage of SDLC is testing.

During the testing stage of SDLC, a quality assurance (QA) expert checks the system to determine whether or not it is functioning properly before it is deployed for operation, which is where the system can be used.

Read more: brainly.com/question/20813142

7 0
3 years ago
Derek needs to shift from his desk to a new work area in his office. Which ergonomic principle should he follow while moving his
Paul [167]

Answer:

One should be in neutral posture, which is the ergonomic principle that needs to be followed while moving our belongings from one location to the other. Its because in this position the work done is zero, and hence we never lose any energy. And this is the posture you should ensure while you are working. Also, the goods packed when moved in this manner, has least chance of wear and tear. Thus, the goods remain safe.

Also, Derek should keep things in a box with padding and then lift to move them to the new work area.

Explanation:

The answer is self explanatory.

3 0
3 years ago
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