Step-by-step explanation:
ur are choosing correct option as,
W = Y ( 90° given )
VW = YZ ( as both are || to eachother so their length is same )
angle X = X ( vertically opposite angle)
therefore, ∆WVX = ∆ZYX are congruent according to SAS congruency rule/criteria.
hope this answer helps you dear..take care and may u have a great day ahead and also ur exam/test goes well!.
We want to find the domain for the graphed function. We will see that the correct option is A: -12 ≤ x ≤ 14
<h3>What is the domain of a function?</h3>
For a function f(x) we define the domain as the set of possible inputs that we can use in the function.
In this case, we need to see the values in the horizontal axis that the graph covers.
We can see that it goes from -12 to 14. We also can see that there are two jumps, at x = -6 and at x = 8, but these values belong to the graph (denoted by the black dot) meaning that these are in the domain.
Then the domain is:
-12 ≤ x ≤ 14
If you want to learn more about domains, you can read:
brainly.com/question/1770447
I will get you started.
x^2+4x-4 = 8
x^2 + 4x - 4 - 8 = 0
x^2 + 4x - 12 = 0
You must now use the quadratic formula.
In the formula, a = 1, b = 4, and c = -12.
Take it from here.
A right triangle has one leg with unknown length, the other leg with length of 5 m, and the hypotenuse with length 13 times sqrt 5 m.
We can use the Pythagorean formula to find the other leg of the right triangle.
a²+b²=c²
Where a and b are the legs of the triangle and c is the hypotenuse.
According to the given problem,
one leg: a= 5m and hypotenuse: c=13√5 m.
So, we can plug in these values in the above equation to get the value of unknown side:b. Hence,
5²+b²=(13√5)²
25 + b² = 13²*(√5)²
25 + b² = 169* 5
25+ b² = 845
25 + b² - 25 = 845 - 25
b² = 820
b =√ 820
b = √(4*205)
b = √4 *√205
b = 2√205
b= 2* 14.32
b = 28.64
So, b= 28.6 (Rounded to one decimal place)
Hence, the exact length of the unknown leg is 2√205m or 28.6 m (approximately).
Answer:
3
Step-by-step explanation:
Because if you take 3.4 you round that 4 down to get just 3.
