Answer:
Step-by-step explanation:
First you want to understand that every time a radio wave goes 300,000,000 meters a second passes, literally what meter per second means. of course it doesn't go that far, it goes 384,000 one way and then the same distance back, which makes 768,000. Under a third of the distance to make 1 second, so it will be less than one second.
You also want to understand the formula for speed. speed = distance / time. Whch also means, to find time you can change it to be time = distance / speed. And hey, we have distance and speed. 768,000 / 300,000,000 = .00256, I'll leave the significant figures to you unless you need help with them. but that's .00256 of a second. or .00256 s
<h3>I'll teach you how to solve 5k^3-8-4k^2+5k^2-2+3k^3</h3>
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5k^3-8-4k^2+5k^2-2+3k^3
Group like terms:
5k^3+3k^3-4k^2+5k^2-8-2
Add similar elements:
5k^3+3k^3+k^2-8-2
Add similar elements:
8k^3+k^2-8-2
Subtract the numbers:
8k^3+k^2-10
Your Answer Is 8k^3+k^2-10
Plz mark me as brainliest :)
Step-by-step explanation:
-2x - 6xy - 3y + 7x <em>combine like terms</em>
= (-2x + 7x) - 6xy - 3y
= 5x - 6xy - 3y
Answer:
I guess that you want to model the elevation of Lake Sam Rayburn.
During the summer, it is 165 ft above the sea level (the sea level is our position 0ft).
If it does not rain, the elevation of the lake decreases by 0.5ft each week.
So if we assume that there is no rain, we can write the elevation fo the lake as a linear relationship with slope equal to -0.5ft and y-intercept equal to 165ft.
L(w) = 165ft - 0.5ft*w
Where w is the number of weeks without rain, if we have 0 weeks without rain, then the level of the lake remains constant at 165ft above sea level,
L(0) = 165ft - 0.
4x - 4y = -36
3x + 4y = 8
7x = -28
/7 /7
x = -4
-4 - y = -9
+4 +4
-y = -5
/-1 /-1
y = 5
(-4 , 5)
