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3 years ago

Is y= 3(1/2)^x increasing or decreasing?

Mathematics

1 answer:

Zigmanuir [339]3 years ago

5 0

Answer: Hey I looked on a graphing calculator on Desmos, and its seems that this is increasing.

Step-by-step explanation:

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Find the zeros of the function g(x) = x^4 - x^3 - 2x^2

solong [7]

set equal to 0

$0=x^4-x^3-2x^2$

factor out the $x^2$

$0=(x^2)(x^2-x-2)$

what 2 numbers multiply to get -2 and add to get -1? -2 and 1

$0=(x^2)(x-2)(x+1)$

set each equal to 0

$0=x^2$

x=0

x-2=0

x=2

x+1=0

x=-1

so the zeroes of the function are at x=-1, 0, 2

6 0

3 years ago

Find the volume of this figure.

ASHA 777 [7]

Answer:

504 and can I get brainliest.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find a closed-form formula that reproduces the sequence 1,-1, 1, -1, 1, -1, 1, ... (zero-based indexing). Check all that are cor

Svetlanka [38]

Recall that

$\cos(0) = \cos(2\pi) = \cos(4\pi) = \cos(2n\pi) = 1$

and

$\cos(\pi) = \cos(3\pi) = \cos(5\pi) = \cos((2n+1)\pi) = -1$

Then the given sequence could be written as

$a_n = \cos(n\pi) = (-1)^n$

7 0

2 years ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of 10 batteries

Nat2105 [25]

Answer:

(1) We are conducting the one-sample t-test and will be testing for the hypothesis of mean battery greater than 25 h. So, we will reject the null hypothesis for mean battery life equal to 25 hr against the alternative hypothesis for mean battery life greater than 25 hr.

(2) A 95% lower confidence interval on mean battery life is 25.06 hr.

Step-by-step explanation:

We are given that a random sample of 10 batteries is subjected to an accelerated life test by running them continuously at an elevated temperature until failure, and the following lifetimes (in hours) are obtained: 25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean BAC = $\frac{\sum X}{n}$ = 26 hr

s = sample standard deviation = $\sqrt{\frac{\sum(X - \bar X)^{2} }{n-1} }$ = 1.625 hr

n = sample of batteries = 10

$\mu$ = population mean battery life

<em> Here for constructing a 95% lower confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

(1) It is stated that the manufacturer wants to be certain that the mean battery life exceeds 25 h.

Since we are conducting the one-sample t-test and will be testing for the hypothesis of mean battery greater than 25 h. So, we will reject the null hypothesis for mean battery life equal to 25 hr against the alternative hypothesis for mean battery life greater than 25 hr.

(2) So, a 95% lower confidence interval for the population mean, $\mu$ is;

P(-1.833 < $t_9$ ) = 0.95 {As the lower critical value of t at 9