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Sav [38]
4 years ago
7

Please help me out!!!!!!!

Mathematics
1 answer:
Alex4 years ago
7 0

the answer is easy just take 2,000 and times it by 2 then 4,000 x 2, then 8,000 x 2, 16,000 x 2, 32000 x 2, 64,000 x 2 <u>the answer is 128,000</u>

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Factor the following expression. 36y - 12
Over [174]

Hey there!


36y - 12


FIRST LOOK AT THE GCF (Greatest Common Factor)


36y: 1, 2, 3, 4, 6, 9, 12, 18, 36, and y


12: 1, 2, 3, 4, 6, and 12


GCF: 12


So, 12 would most likely be number before you make your parentheses


12(?y - 1)


The numbers in your original equation both share 3 & -1


So, therefore the factor form of your equation should be: 12(3y - 1)


Answer: 12(3y - 1)


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

7 0
2 years ago
Read 2 more answers
5x^2-23x+12<br>this is the question im stuck on
AURORKA [14]
Rewrite it as 5x^2 -20x-3x+12
then (5x^2 -20x)(-3x+12)
then use gcf and u will get the answer in a binomial form
8 0
3 years ago
A Walmart truck driver estimates that it will take him 12 hours to drive 1152 km. After 5 hours, he has driven 520 km.
san4es73 [151]

(a) He would drive 96 km in an hour because 1152 divided by 12 is 96

(b) He is technically on schedule because he is driving 104 km per hour, instead of 96, so if he keeps driving at the same rate, he should get there in under 12 hours

6 0
3 years ago
Classify the scatter plot as having a negative or no correlation. HOMEWORK DUE TOMORROW
Katarina [22]
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3 0
3 years ago
A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of
ddd [48]

There are

\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}

ways of pairing up any 2 members from the pool of 2n contestants. Note that

(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)

so that

\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}

4 0
2 years ago
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