Answer:
10.53m/s²
Explanation:
Centripetal acceleration is the acceleration of an object about a circle. The formula for calculating centripetal acceleration is expressed by:
v is the velocity of the car = 24.5m/s
r is the radius of the track = 57.0m
Substitute the given values into the formula:
Hence the centripetal acceleration of the race car is 10.53m/s²
The speed of the boy and his friend at the bottom of the slope is 16.52 m/s.
<h3>Their speed at the bottom</h3>Apply the principle of conservation of energy,
E(up) - E(friction) = E(bottom)
mg sin(15) + ¹/₂(M + m)u² - μ(M + m)cos 15 = ¹/₂(M + m)v²
where;
u = √2gh
u = √(2gL sin15)
u = √(2 x 9.8 x 28 x sin 15)
u = 11.92 m/s
Thus, the speed of the boy and his friend at the bottom of the slope is 16.52 m/s.
Learn more about speed here: brainly.com/question/6504879
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To develop this problem it is necessary to apply the concepts related to electromagnetic energy and Broglie's hypothesis.
By definition we know that the electrical energy of a proton can be expressed as
E = qV
Where,
q = Charge of proton
V = Voltage
Replacing with our values
E = qV
It is necessary to add the two potentials
From Broglie's hypothesis we know that the wavelength is given by
Where,
h = Planck's constant
p = Momentum
The momentum of a particle can be expressed in terms of energy, that is,
Where,
m = mass
E = Energy (potential or kinetic)
Therefore replacing this value at lambda,