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Bess [88]
3 years ago
12

PLEASE HELP, DUE TOMORROW​

Mathematics
1 answer:
navik [9.2K]3 years ago
5 0

Answer:

2% (rounded to nearest percent)

Step-by-step explanation:

The formula is already given.

From the problem, we can say that:

Actual Value = 13.6

Experimental Value = 13.3

To find percentage error, we use the formula [remember, the numerator of the formula has absolute value, so if we find any negative answer, that would becomes positive value]. lets do this:

Percent Error = \frac{|13.3-13.6|}{13.6}*100\\=\frac{|-0.3|}{13.6}*100\\=\frac{0.3}{13.6}*100\\=0.0221*100\\=2.21

So, 2.21%

Rounded to nearest percent, that would be 2%

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Which are the roots of the equation 3m^2-5m+1=0
Svetradugi [14.3K]

Answer:

       -(-5) ± √13             5 ± √13

x = ----------------------- = ---------------

              2(3)                       6

Step-by-step explanation:

This is a quadratic equation, with coefficients 3, -5 and 1.

The discriminant, b² - 4ac, turns out to be (-5)² - 4(3)(1), or 25 - 12  =  13

Thus, the roots are:

       -(-5) ± √13             5 ± √13

x = ----------------------- = ---------------

              2(3)                       6

8 0
3 years ago
Pls help due in 10 mins
BabaBlast [244]

Answer:

Try inserting the Problem

Step-by-step explanation:

6 0
3 years ago
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Ostrovityanka [42]
X=22

Area is found by multiplying (x+7)and (2x-1) together. 22+7=29, 2(22) -1 = 43, 43+29=72
3 0
3 years ago
Two friends share 7 cookies equally. How many cookies does each friend get?​
victus00 [196]
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3 years ago
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How would you find values of m for question 'b'?
Trava [24]
This is known as quadratic algebra.

To find it, you can use the quadratic formula but that might take a while.

We can factor it out and get

-3(mx² + mx - 1)

We can then set mx² + mx = 1

It would have no solutions

Edit: Above is wrong!  I made the mistake of factoring 3 when it cant be factored.  

Here is the solution

mx²-3mx=-3

Divide both by -3

mx²+mx=1

And I really messed this up.  Its been a long time since quad.  Sorry, but I cant seem to get the answer.  Try and look up the quadratic formula and see if you can use that


6 0
4 years ago
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