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3 years ago

60+6=48 What is the value of b?

Mathematics

1 answer:

mina [271]3 years ago

3 0

Answer:

-2

Step-by-step explanation:

Assuming you mean 60 + 6b = 48

subtract 60 from both sides: 6b = 48 - 60 = -12

Now divide both sides by 6 to solve for b: b = -12/6 = -2

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If a histogram is right skewed, which will be greater the mean or the median? Type a single word answer in the space

Mandarinka [93]

Answer:

Mean is greater

Step-by-step explanation:

For a skewed distribution, then the tail is longer to one side from the center than to the other. In a right skewed distribution, the tail is longer to the right.

When a distribution is skewed, the mean will be closer to the tail Than the median. Therefore. For a right skewed histogram, the mean is closer to the tail of the histogram and hence closer to the right. Once this happens, values closer to the right of a distribution are higher (number line). Thus the mean will be greater than the median.

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2 years ago

One day, eleven babies are born at a hospital. Assuming each baby has an equal chance of being a boy or girl, what is the probab

Andrews [41]

You only need to consider the situations where 10 or 11 of the babies are girls, then subtract those probabilities from 1. This will give probability that any other number up to 9 of the babies are girls.

Use binomial theorem.
$P(x=k) = (nCk) p^k (1-p)^{n-k}$

n = 11
k = 10,11
p = 1/2

$P(x=10) = 11 (\frac{1}{2})^{11} = \frac{11}{2048} \\ \\ P(x=11) = 1(\frac{1}{2})^{11} = \frac{1}{2048} \\ \\ P(x \leq 9) = 1 - \frac{11}{2048} - \frac{1}{2048} \\ \\ P(x \leq 9)=\frac{2036}{2048} = \frac{509}{512}$

4 0

3 years ago

Can someone please answer. There is a picture. There is only one problem. Thank you so much!!!

Darya [45]

Second answer is correct

5 0

3 years ago

What is the value of (fog) (-5)

DochEvi [55]

$f(x)=2x+1,\ g(x)=x^2\\\\(f\circ g)(x)=2(x^2)+1=2x^2+1\\\\(f\circ g)(-5)=2(-5)^2+1=2(25)+1=50+1=51$

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3 years ago

Suppose n(X) = 28 and n(Y) = 19.

Flauer [41]

$n(X\cup Y)=n(X)+n(Y)-n(X\cap Y)$

If $X$ and $Y$ share no common elements, then $n(X\cap Y)=0$ , which means $n(X\cup Y)=n(X)+n(Y)=47$

On the other hand, if the smaller set is entirely contained within the larger set, i.e. $Y\subseteq X$ , then $X\cap Y=Y$ , and so $n(X\cup Y)=n(X)+n(Y)-n(Y)=n(X)=28$ .

8 0

3 years ago