Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
Answer:
We know
1 jar = 500 buttons
5 people bring 330 buttons EACH
We can find/solve by...
people x buttons = total buttons
total buttons / 500 = number of jars needed
So..
5 x 330 = 1650
1650 / 500 = 3.3
Your answer:
4 jars
Explanation
It's impossible to have 3.3 jars, so you must round up.
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
Answer:
x(12x^2+18x)
Step-by-step explanation:
x(12x^2+18x)=12x^(3)+18x^2
Answer:
slope: -3
y-intercept: 5
Step-by-step explanation:
y=mx+b, where m=slope and b=y-intercept
