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Rashid [163]
3 years ago
13

A teacher handed out 10 notebooks in packs with 5 notebooks in each pack. How many packs were there?

Mathematics
1 answer:
lozanna [386]3 years ago
7 0

Answer:

2 packs

Step-by-step explanation:

Since there is 10 packs just divided it by how many notebooks were in the pack.

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Use a given information to create equation for the rational function. The function is written in factored form to help see how t
Mars2501 [29]

Recall that a rational function:

\frac{P(x)}{Q(x)},

has a vertical asymptote at x₀ if and only if:

Q(x_0)=0.

Also, the roots of the above rational function are the same as P(x).

Since the rational function has a vertical asymptote at x=-1, we get that its denominator must be:

Q(x)=x+1\text{.}

Since the rational function has a double zero at x=2 we get that its numerator must be of the form:

P(x)=k(x-2)(x-2)\text{.}

Finally, since the rational function has y-intercept at (0,2) we get that:

2=\frac{P(0)}{Q(0)}=\frac{k(0-2)(0-2)}{0+1}\text{.}

Simplifying the above equation we get:

\begin{gathered} \frac{k(-2)(-2)}{1}=2, \\ 4k=2. \end{gathered}

Dividing the above equation by 4 we get:

\begin{gathered} \frac{4k}{4}=\frac{2}{4}, \\ k=\frac{1}{2}\text{.} \end{gathered}

Therefore, the rational function that satisfies the given conditions is:

f(x)=\frac{\frac{1}{2}(x-2)(x-2)}{x+1}\text{.}

Answer:

The numerator is:

\frac{1}{2}(x-2)(x-2)

The denominator is:

(x+1)

4 0
1 year ago
The function y = -x + 4 has to main of {0.3,6). What is its range?
Komok [63]

Answer:

i think it's A if I'm wrong then wow

4 0
3 years ago
How much honey does a beekeeper take from the hive
juin [17]
A milllion probably like 1 million
7 0
3 years ago
Read 2 more answers
I need help bbbbbbbb​
Sav [38]
Answer: 180cm


Explanation:

The area of a triangle is 1/2(b)(h).
The height of the triangles is 12cm and the base is 6cm.

1/2(6)(12) = 36cm
Multiply by 4 = 144


For square: 6 • 6 = 36cm


144cm + 36cm = 180cm
8 0
3 years ago
Find an equation of the plane through the point (−1,−5,−2)(−1,−5,−2) with normal vector n=⟨−5,−4,−1⟩n=⟨−5,−4,−1⟩.
Ostrovityanka [42]
Consider this option:
1. given: n(A;B;C)=n(-5;-4;-1) and A(-1;-5;-2)=A(x₀;y₀;z₀).
Common view of equation for a plane is Ax+By+Cz+D=0, where A,B,C,D - numbers.
2. from another side using coordinates of A and normal vector it is possible to make up the equation: A(x-x₀)+B(y-y₀)+C(z-z₀)=0 ⇒ -5(x+1)-4(y+5)-(z+2)=0; ⇒ -5x-4y-z-27=0 or 5x+4y+z+27=0.
7 0
3 years ago
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