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Sergio [31]
3 years ago
15

Which number is prime? A. 4 B. 10 C. 22 D. 31

Mathematics
2 answers:
Ganezh [65]3 years ago
7 0

Answer:

D. 31

31 is prime

lisov135 [29]3 years ago
7 0

Answer:

d. 31

Step-by-step explanation:

BRAINLIEST PLEASE

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I need a little help
yanalaym [24]

Answer:

450 simple

Step-by-step explanation:

3 0
2 years ago
Please answer it as fast as u can ​
Vadim26 [7]

Answer:

Am I missing something to this question?

As pictured, the answer is 12 7/9ths.

7 0
3 years ago
The height of a ball dropped from the top of a 450-foot tall building can be described by the expression
BaLLatris [955]

Answer:

The answer is 386 feet.

Step-by-step explanation:

This equation simply asks to plug in a value that gives you the final value of the height. 450 is the initial height, and r (or l) is referred to as the amount of seconds after the item is dropped. 16 is the constant value of feet that the ball drops within one second.

Therefore, by substituting 4 for r (or l) and multiplying it by 16, you will receive 64 feet in 4 seconds. Finally, you need to subtract this from 450 feet, giving you a final answer of 386 feet.

8 0
3 years ago
What is a estimate of 7/10 times 16 uses a benchmark fraction
Annette [7]
The answer is 11 1/5
6 0
3 years ago
Read 2 more answers
Each letter of the word "supercalifragilisticexpialidocious" is placed into a bag and drawn at 3 times, replacing the letter aft
Makovka662 [10]

Answer:

P(X ≥ 1) = 0.50

Step-by-step explanation:

Given that:

The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.

Then; the probability of success = 7/34 = 0.20588

Using Binomial distribution to determine the probability; we have:

P(X = x)  = ^nC_x  \ \beta^x   \  (1 - \beta)^{n-x}

where;

x = 0,1,2,...n    and    0  <  β   <   1

and x represents the  number of successes.

However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:

P(X ≥ 1) = 1 - P(X< 1)

P(X ≥ 1) = 1 - P(X =0)

P(X \ge 1) =  1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]

P(X \ge 1) =  1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]

P(X ≥ 1) = 1 - 0.50

P(X ≥ 1) = 0.50

4 0
3 years ago
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