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scoray [572]
3 years ago
13

From 2000 to 2006, the number of students enrolled at a state university increased

Mathematics
1 answer:
coldgirl [10]3 years ago
7 0

Answer:

The enrollment in year 2000 was about 1371  

Step-by-step explanation:

Given as :

The number of student enrolled at university in 2006 was 10,325

The increased percentage of student from 2000 to 2006 is 40%

Let the number of students in year 2000 was x

The number of student in 2006 = The number of student in 2000 × ( (1 +\frac{40}{100})^{6}

Or, 10,325 = x ×( (1 +\frac{40}{100})^{6}

Or, 10,325 = x × (\frac{140}{100})^{6}

Or, 10,325 = x × 7.529

∴ x = \frac{10,325}{7.529}

So, x = 1371.364

Hence The enrollment in year 2000 was about 1371    Answer

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In your biology class, your nal grade is based on several things: a lab score, scores on two major tests, and your score on the
Mariana [72]

Complete Question

In your biology class, your final  grade is based on several things: a lab score, scores on two major tests, and your score on the final exam. There are 100 points available for each score. However, the lab score is worth 25% of your total grade, each major test is worth 22:5%, and the final exam is worth 30%. Compute the weighted average for the following scores: 92 on the lab, 81 on the first major test, 93 on the second major test, and 85 on the final exam. (Enter your answer to one decimal place)

Answer:

The weighted average is  W = 87.65

Step-by-step explanation:

From the question we are told that

  The worth of the lab score is  25% of total grade

  The worth of each major  test is   22.5% of total grade

   The worth of final exam is  30% of total grade

The  score on lab is  92

The score on first major test 81

The score on second major test 93

 The score on final  exam is  85

Generally the weighted score is mathematically represented as

     W = 0.25 *  92 + 0.225* 81 + 0.225* 93 +0.30 * 85

=> W = 0.25 *  92 + 0.225* 81 + 0.225* 93 +0.30 * 85

=> W = 87.65

   

   

3 0
3 years ago
It is believed that 11% of all Americans are left-handed. In a random sample of 100 students from a particular college with 1012
tia_tia [17]

Answer:

Step-by-step explanation:

We can calculate this confidence interval using the population proportion calculation. To do this we must find p' and q'

Where p' = 14/100= 0.14 (no of left handed sample promotion)

q' = 1-p' = 1-0.14= 0.86

Since the requested confidence level is CL = 0.98, then α = 1 – CL = 1 – 0.98 = 0.02/2= 0.01, z (0.01) = 2.326

Using p' - z alpha √(p'q'/n) for the lower interval - 0.14-2.326√(0.14*0.86/100)

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= -2.186*0.057

= 12.46%

Using p' + z alpha √(p'q'/n)

0.14+2.326√(0.14*0.86/100)

= 0.466*0.057

= 26.5%

Thus we estimate with 98% confidence that between 12% and 27% of all Americans are left handed.

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Answer:

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Step-by-step explanation:

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