All categories

3 years ago

How do I find the x and y of -2 +3y=15 and 2x+3y=15

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

You can use MathPapa it will help you

You might be interested in

Is 1,250 More than or less than 1.25

sweet [91]

1,250 is more then 1.25 because it’s a greater number

5 0

3 years ago

Read 2 more answers

Determine how long it will take for $4000 to quadruple in a bank account earning 3.57% interest compounded continuously. Round t

tankabanditka [31]

Answer:

12 months, so 1 year

Step-by-step explanation:

5 0

3 years ago

Match the phenomenal expression on the left with the simplified version on the right

nalin [4]

Given the polynomial expression:

(y + 5)²

(y - 5)(y + 5)

Let's simplify each of the given expression:

a.) (y + 5)²

The given equation is a factor of a perfect square trinomial. For this type of expression, the following is the formula for expanding it.

$\text{ (a+b)}^2\text{ = }a^2\text{ + 2ab + }b^2$

We get,

$\mleft(y+5\mright)^2=(y)^2+2(y)(5)+(5)^2$ $(y+5)^2=y^2+10y+25$

b.) (y - 5)(y + 5)

To be able to simplify the following expression. We will be using the formula for the difference of two squares.

$(a+b)(a-b)=a^2-b^2$

We get,

$\mleft(y-5\mright)\mleft(y+5\mright)=(y)^2-(5)^2$ $(y-5)(y+5)=y^2-25^{}$

8 0

1 year ago

A polynomial has been factored, as shown below: f(x) = (x − 6)(x + 5)(x − 9) What are the zeros of the polynomial? (5 points)

soldi70 [24.7K]

x=6, x=−5 or x=9

Explanation:

f(x)=(x−6)(x+5)(x−9)

If all of the linear factors are non-zero, then so is their product f(x).

If any of the linear factors is zero, then so is their product f(x).

5 0

3 years ago

Special right triangles, find x and y

egoroff_w [7]

Answer:

The answer to your question is x = 17.32; y = 8.67

Step-by-step explanation:

Process

1.- Use trigonometric functions to find x and y

a) sin Ф = $\frac{opposite side}{hypotenuse}$

Ф = 60°

opposite side = 15

hypotenuse = ?

$hypotenuse = \frac{opposite side}{sin \alpha }$

$hypotenuse = \frac{15}{sin 60}$

$hypotenuse = \frac{15}{0.87}$

hypotenuse = 17.32

b) cosФ = $\frac{y}{hypotenuse}$

$y = hypotenuse x cos 60$

$y = 17.32 x 0.5$

y = 8.67

5 0

3 years ago