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ikadub [295]
4 years ago
13

How do I find the x and y of -2 +3y=15 and 2x+3y=15

Mathematics
1 answer:
vladimir1956 [14]4 years ago
6 0
You can use MathPapa it will help you
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What is the answer to -5x+5y=-10 and 3x-3y=5 using substitution
IceJOKER [234]

Answer:

for the 1st one the answer is x= 3 y=1 and the second one is x= 5 and y = 3 and 1/3

Step-by-step explanation: so basically for the first one -5 times x which is 3 is -15 right? and then 5 times y which is 1 is 5 right so -15 plus 5 = -10

second one is x = 5 and y = 3 and 1/3 because 5*x which is 5 is = to 15 right? and then 3 times y which is equal to 3 and 1/3 is equal to 10 which when you do 15-10 in pretty sure it equals 5 correct me if im wrong

Hope this helps xD ;)

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4 years ago
Marni and Mikela are playing a color-guessing game. Each player chooses two colors from a list of red (R), blue (B), green (G),
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The answer should be 1/2.

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4 years ago
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Find the product. Write your answer in scientific notation. (3 x 10^2)×(4×10^5) ​
suter [353]

Answer:

12 * 10 ^ 7

Step-by-step explanation:

3 * 10 ^ 2 * 4 * 10 ^5

= 12 * 10^ 2 + 5

= 12 * 10 ^ 7

Hope it will help :)

7 0
3 years ago
Elijah works at Chick-fil-A and gets paid weekly. He does not have any money in his bank account yet, but will
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What is the question?
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The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act
ira [324]

Answer:

The standard deviation would have to be 0.05.

Step-by-step explanation:

We can solve this problem using the 68-95-99.7 rule for normal distributions:

The rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

What would the value of σ have to be to ensure that 95% of all readings are within 0.1° of μ?

This means that 2 standard deviations would need to be within 0.1 of the mean. So

2\sigma = 0.1

\sigma = \frac{0.1}{2}

\sigma = 0.05

The standard deviation would have to be 0.05.

6 0
3 years ago
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