How do I find the x and y of -2 +3y=15 and 2x+3y=15

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

You can use MathPapa it will help you

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The equation $a^7xy-a^6y-a^5x=a^4(b^4-1)$ is equivalent to the equation $(a^mx-a^n)(a^py-a^2)=a^4b^4$ for some integers $m$, $n$

Ksivusya [100]

Let simplify the equations $a^7xy-a^6y-a^5x=a^4(b^4-1)$ and $(a^mx-a^n)(a^py-a^2)=a^4b^4$ :

1) $a^7xy-a^6y-a^5x+a^4=a^4b^4$

and

2) $a^{m+p}xy-a^{n+p}y-a^{m+2}x+a^{n+2}=a^4b^4$ .

Equate the coefficients:

 $xy: m+p=7 \\ y: n+p=6 \\ x: m+2=5 \\ 1: n+2=4$ .
Then $n=2 \\ p=4 \\ m=3$ and mnp=24.

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3 years ago

Find the unit price of 8 mugs for $38.32 A.) $4.99 B.) $4.97 C.) $4.79 D.) $4.77

Anastasy [175]

Answer:

C. 4.79

Step-by-step explanation:

I divided 38.32 by 8 to find the individual prices

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2 years ago

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