H = -5t^2 +5t + 10
a) t = 0, h = 10 at time 0
b) h = (-5t + 10) ( t + 1)
c) put 0 in for the height and set each factor = to 0 and solve each
0 = (-5t + 10) and 0 = (t + 1)
solve each t = 2 and t = -1, so t = 2 sec is your solution
d) because a parabola is symmetric, the max will be half way between -1 and 2, at t = 1/2
h = -5(1/2)^2 +5(1/2) + 10
h = -5(1/4) + 5/2 +10
h = -5/4 + 5/2 + 10
h = -5/4 + 10/4 + 40/4
h = 45/4
Answer:94%
Step-by-step explanation:
Half life of a radioactive element is the time taken for half it's mass to disintegrate away.it means after attaining half life,what will be left is 100-50=50%.
Let the 100% mass of C-14,be x
Then 5730years=1/2 of X
Then 660 years=y of X
Where Y is the fraction of C-14 that has disintegrate as at 1988.
5730/660=1/2X/yX
5730/660=1/2/y
Cross multiplying
5730×y=660×1/2
5730y=330
Y=330/5730=0.05759
In %,5.76%
Amount of C-14 left is
100-5.76=94.24=94% as at 1988.
A = 1
b = -2
c = -3
And when you plug in and solve you'll get correct answers of x = 3 and x = -1
Answer:
sorry but this photo is not clear
