Answer:
12 rolls
Step-by-step explanation:
Jason wants to cut roll into pieces that are each 1/2 inches thick. 1/2 is equal to 0.5, so thickness of each roll is 0.5 inches
Total length of the roll is 6 inches. We have to find how many small 0.5 inch rolls can he cut.
In simple words we can say that we have to find: how many 0.5 inches can be out from 6 inches. This type of problem is solved by division. Dividing 6 inches by 0.5 inches will give us: How many 0.5 inches can be cut out from 6 inches i.e. how many 0.5 inches roll can be made from 6 inches roll
6 divided by 0.5 is 12.
This means Jason can cut 12 rolls of sausages each with thickness of 0.5 inches from a roll of 6 inches.
There's more than one way to do this problem.
Try this: Mult. both 109 and 5 by 2, obtaining 218 and 10.
What is 218 div. by 10? Do this in your head.
Answer:
Part A: YES, it is.
Part B: the amount of pumpkin picked and the amount of fertilizer applied.
Step-by-step explanation:
Part A:
The closer the correlation coefficient is to 1, the stronger the relationship between two variables, and vice versa. Also, the closer the data points are on a scatter plot, the closer the correlation coefficient is to 1.
The scatter plot shown indicates a positive correlation between number of days and number of pumpkins. However, the data points are to some extent farther apart from each other. This shows a moderate relationship between the two variables. Therefore, a correlation coefficient, r, of 0.51 that was calculated can be concluded to be accurate , because an r of 0.51 depicts a moderate relationship between two variables.
Part B:
A variable that could affect the number of pumpkins picked could be amount of fertilizer applied, instead of the day in October. Thus, we can compare the amount of pumpkin picked and the amount of fertilizer applied.
Answer:
<u>96 ft</u> is the perimeter of the figure.
Step-by-step explanation:
9 + 9 + 9 + 9 + 9 + 9 + 12 + 30 = 96
Have a nice day!
Answer:
202500
Step-by-step explanation:
15x0.45=6.75
30000x6.75=202500
