He sold 37 albums.
$644-$200= $444
$444÷$12= 37
Hope this helps! :)
\(^ ◇^)/
<u>NOT</u> Answer: B
Step-by-step explanation:
Don't try and use the wrong answer below!
Answer:
1 7/8
Step-by-step explanation:
The first step is to find the least common denominator of 3/8 and 9/4, or the least common multiple of 8 and 4. LCD is 8. Make the denominators the same as the LCD.
-3/8 + 9/4x2
-3/8 + 18/8
-3+18/8
15/8
1 7/8
Hope this helps!:) Best of luck!
Answer:
0.014 or 1.4% of connectors fail during the warranty period.
Step-by-step explanation:
Consider the provided information.
Let: D = electrical connector is dry
D' = electrical connector is not kept dry (i.e., is wet)
F = connector fails during warranty period
F' = connector does not fail during warranty period
90% of the connectors are kept dry
That means P(D)=0.9
10% are wet,
P(D')=0.1
The probability is 1% that an electrical connector that is kept dry fails during the warranty period, i.e.
P(F|D)=0.01
If the connector is ever wet, the probability of a failure during the warranty period is 5%, i.e.
P(F|D')=0.05
![P(F)=P(D)\times P(F|D)+P(D')\times P(F|D')\\P(F)=0.9\times 0.01+0.1\times 0.05\\P(F)=0.014](https://tex.z-dn.net/?f=P%28F%29%3DP%28D%29%5Ctimes%20P%28F%7CD%29%2BP%28D%27%29%5Ctimes%20P%28F%7CD%27%29%5C%5CP%28F%29%3D0.9%5Ctimes%200.01%2B0.1%5Ctimes%200.05%5C%5CP%28F%29%3D0.014)
Hence, 0.014 or 1.4% of connectors fail during the warranty period.
the mean is 50.5, but rounded it's 51.