Answer:
Spring constant, K = 415.9 N/m
Explanation:
The period of vibration of a spring, T, is given by:
T = 2√m/K
Where m = mass of the body in kg, K = spring constant or force constant or elastic constant or stiffness in Nm-1
Making K the subject of the expression,
K = m(2)2/(T)2
K = 4m()2/(T)2
Where m = 0.38kg, = 3.14285714286, T = 0.19s
K = 4 x 0.38 (3.14285714286)2 / (0.19)2
K = 4 x 0.38 x 9.87755102043 / 0.0361
K = 15.0138775511 / 0.0361
K = 415.9 Nm-1
