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Anvisha [2.4K]
3 years ago
7

Technician A says that studs should be installed finger tight. Technician B says that studs must be installed using a thread loc

ker such as Locktite. Which technician is correct?
Computers and Technology
1 answer:
alexandr402 [8]3 years ago
3 0

The correct answer is; both technicians are correct.

Further Explanation:

The studs can be installed using both methods. The thread locker is used by many people daily when installing studs and this causes no issues. The studs can also be installed finger tight and still have no issues. So both technicians are correct.

When putting together an engine, there are some types things that must be used only with the thread locker to get the right fit and this will make the bolt doesn't move. Same with screwing something in and it only being finger tight, many things on an engine can't be so tight that they can't be taken back off easily.

Learn more about car engines at brainly.com/question/10736767

#LearnwithBrainly

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given an array of integers a, your task is to count the number of pairs i and j (where 0 ≤ i < j < a.length), such that a[
Nimfa-mama [501]

Using the knowledge of computational language in C++ it is possible to write a code that given an array of integers a, your task is to count the number of pairs i and j.

<h3>Writting the code:</h3>

<em>// C++ program for the above approach</em>

<em> </em>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em> </em>

<em>// Function to find the count required pairs</em>

<em>void getPairs(int arr[], int N, int K)</em>

<em>{</em>

<em>    // Stores count of pairs</em>

<em>    int count = 0;</em>

<em> </em>

<em>    // Traverse the array</em>

<em>    for (int i = 0; i < N; i++) {</em>

<em> </em>

<em>        for (int j = i + 1; j < N; j++) {</em>

<em> </em>

<em>            // Check if the condition</em>

<em>            // is satisfied or not</em>

<em>            if (arr[i] > K * arr[j])</em>

<em>                count++;</em>

<em>        }</em>

<em>    }</em>

<em>    cout << count;</em>

<em>}</em>

<em> </em>

<em>// Driver Code</em>

<em>int main()</em>

<em>{</em>

<em>    int arr[] = { 5, 6, 2, 5 };</em>

<em>    int N = sizeof(arr) / sizeof(arr[0]);</em>

<em>    int K = 2;</em>

<em> </em>

<em>    // Function Call</em>

<em>    getPairs(arr, N, K);</em>

<em> </em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/17544466

#SPJ4

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