Answer:
Try going to your settings and allow output camera
Explanation:
Answer:
I am writing the function using Python. Let me know if you want the program in some other programming language.
def iterPower(base, exp):
baseexp = 1
while exp > 0:
baseexp = baseexp*base
exp= exp - 1
return baseexp
base = 3
exp = 2
print(iterPower(base, exp))
Explanation:
- The function name is iterPower which takes two parameters base and exp. base variable here is the number which is being multiplied and this number is multiplied exponential times which is specified in exp variable.
- baseexp is a variable that stores the result and then returns the result of successive multiplication.
- while loop body keeps executing until the value of exp is greater than 0. So it will keep doing successive multiplication of the base, exp times until value of exp becomes 0.
- The baseexp keeps storing the multiplication of the base and exp keeps decrements by 1 at each iteration until it becomes 0 which will break the loop and the result of successive multiplication stored in baseexp will be displayed in the output.
- Here we gave the value of 3 to base and 2 to exp and then print(iterPower(base, exp)) statement calls the iterPower function which calculates the exponential of these given values.
- Lets see how each iteration works:
baseexp = 1
exp>0 True because exp=2 which is greater than 0
baseexp = baseexp*base
= 1*3 = 3
So baseexp = 3
exp = exp - 1
= 2 - 1 = 1
exp = 1
baseexp = 3
exp>0 True because exp=1 which is greater than 0
baseexp = baseexp*base
= 3*3 = 9
So baseexp = 9
exp = exp - 1
= 1-1 = 0
exp = 0
- Here the loop will break now when it reaches third iteration because value of exp is 0 and the loop condition evaluates to false now.
- return baseexp statement will return the value stored in baseexp which is 9
- So the output of the above program is 9.
Answer:
#include <iostream>
using namespace std;
int * reverse(int a[],int n)//function to reverse the array.
{
int i;
for(i=0;i<n/2;i++)
{
int temp=a[i];
a[i]=a[n-i-1];
a[n-i-1]=temp;
}
return a;//return pointer to the array.
}
int main() {
int array[50],* arr,N;//declaring three variables.
cin>>N;//taking input of size..
if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..
return 0;
for(int i=0;i<N;i++)
{
cin>>array[i];//prompting array elements..
}
arr=reverse(array,N);//function call.
for(int i=0;i<N;i++)
cout<<arr[i]<<endl;//printing reversed array..
cout<<endl;
return 0;
}
Output:-
5
4 5 6 7 8
8
7
6
5
4
Explanation:
I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.
Answer:
Laser beams.
Explanation:
Recently, that user has began functioning part-time in such a retail outlet, as well as he discovering regarding his shop's learning tools. During checkout, his shop requires the code scanner to scan objects.
The barcode scanner uses laser beam technologies because the laser beam is rapidly running over the QR code or barcode back-and-forth, or executing the sequence. The sensors well into the system display the mirrored beam patterns that decrypts the barcode.
So, the following are the reason that describes the answer is correct according to the scenario.
Technological advancements during the industrial age provided Americans with option B) More leisure times.
<h3>What were some technological advancements during the age of industry?</h3>
The growth in productivity is one that started with a little technical devices, such as the spinning jenny, spinning mule, and others.
Note that Technological advancements during the industrial age provided Americans with option B) More leisure times as machines does the work.
Learn more about Technological advancements from
brainly.com/question/2166344
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