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icang [17]
3 years ago
13

Sixteen is divided by the sum of a number q and 1

Mathematics
1 answer:
atroni [7]3 years ago
4 0

No context. If you want us to write an expression:

16 / (q+1)

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Choose the possible descriptions of cross sections formed by the intersection of a plane and a cylinder choose all that apply
nasty-shy [4]

Answer:

circle and rectangle

Step-by-step explanation:

we know that

A cross section that is perpendicular to the base of cylinder is a rectangle

A cross section that is parallel to the base of cylinder is a circle

A cross section that is angled to the base of cylinder is an oval

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Can you cut a pizza into eleven pieces using exactly four straight cuts?
Anastaziya [24]
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Complete the following statement.
solong [7]

Answer:

Hello dude

- 1 \frac{21}{24}  + 1 \frac{22}{24}  =  +  \frac{1}{24}

so it's positive

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Step-by-step explanation:

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What is the solution to<br> 3×+7-8×+3&gt;0?
horsena [70]

The answer to the equation is x < 2.

7 0
3 years ago
Read 2 more answers
The graph 4x^2-4x-1 is shown. Use the grpah to find the estimates for the solutions of 4x^2-4x-1=0 and 4x^2 - 4x-1=2
Darina [25.2K]

Answer:

a) The estimates for the solutions of 4\cdot x^{2}-4\cdot x -1 = 0 are x_{1}\approx -0.25 and x_{2} \approx 1.25.

b) The estimates for the solutions of 4\cdot x^{2}-4\cdot x -1 = 2 are x_{1}\approx -0.5 and x_{2} \approx 1.5

Step-by-step explanation:

From image we get a graphical representation of the second-order polynomial y = 4\cdot x^{2}-4\cdot x -1, where x is related to the horizontal axis of the Cartesian plane, whereas y is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case:

a) 4\cdot x^{2}-4\cdot x -1 = 0

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

x_{1}\approx -0.25, x_{2} \approx 1.25

b) 4\cdot x^{2}-4\cdot x -1 = 2

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

x_{1}\approx -0.5, x_{2} \approx 1.5

5 0
3 years ago
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