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4 years ago

Maria’s dog weighs six times as much as a rabbit. together the pets weight 56 pounds what does Maria’s dog weigh?

1 answer:

3 0

Well first we can create and equation to get and x will stand for the pets weight 56=6x+x now we simplify to get 56=7x divide each side by 7 and we get 8=x
therefore her dog weighs 48 pounds

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Find the missing measurements and round to the nearest tenth

Bingel [31]

Answer:

Radius=3

Diameter=6

Circumference=18.85

Step-by-step explanation:

3x2

C=2πr=2·π·3≈18.84956

4 0

3 years ago

Read 2 more answers

Find the value of x in each of the given figures.

Kaylis [27]

Answer:

Step-by-step explanation:

1) Given figure is a parallelogram

Area = 144 cm²

base * altitude = 144

16 * x = 144

x =144/16

x = 9 cm

2)2) Trapezium

Area = $\frac{a+b}{2}*h$ ; {a and b are parallel sides of trapezium}

( 37 +27 /2) * x = 480 cm²

64/2 * h = 480

32 * h = 480

h = 480/32

h = 15 cm

8 0

4 years ago

3 1/8 - 1 7/8 =__ _/8<br> (Write your answer as a mixed number.)

Vikentia [17]

2 1/8

to solve you need to convert 3 1/8 and 1 7/8 improper fractions. wicth is 25/8 and 8/8. then subtract the numerators and keep the denominators the same. it would equal 17/8. and finally you need to convert it back to a mixed number by dividing the numerator by the denominator and putting the remaining as the numerator witch equals 2 1/8

4 0

3 years ago

Janie bought 8 apples and 6 bananas. Each apple costs $0.80, and each banana cost $.60. Answer an expression representing the to

Pavel [41]

A: apples
b: bananas

Your expression could be:

$0.80a + $0.60b = $10.00

----

$0.80 ( 8 ) + $0.60 ( 6 ) = $10.00
$6.40 + 3.60 = $10.00
$10.00 = $10.00
✔

3 0

3 years ago

Select the best answer for the question

Klio2033 [76]

Answer:

C. $\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]$

Step-by-step explanation:

The given matrices are;

$F=\left[\begin{array}{cc}-2&0\\0&8\\2&1\end{array}\right]$

and

$C=\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]$

$FC=\left[\begin{array}{cc}-2&0\\0&8\\2&1\end{array}\right]\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]$

$FC=\left[\begin{array}{ccc}12(-2)+0(1)&0(-2)+-6(0)&\frac{3}{2}(-2)+7(0)\\12(0)+8(1)&0(0)+8(-6)&0(\frac{3}{2})+8(7)\\2(12)+1(1)&2(0)+1(-6)&2(\frac{3}{2})+1(7)\end{array}\right]$

This simplifies to;

$FC=\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]$

The correct answer is C

5 0

3 years ago