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postnew [5]
2 years ago
5

1) For what values is the statement true? sin(x+20)°=cos(y−10

Mathematics
1 answer:
iragen [17]2 years ago
5 0

Answer:

1) X =20° ,Y=60°

2) 7/5

3) first is correct

4) 2

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Can so.eone explain to me by what bisecting intervals are?​
Tasya [4]

When you bisect something, you cut it into two equally sized pieces. (from Latin: "bi" = two, "sect" = cut)

Bisecting an interval creates two smaller intervals each with half the length of the original interval. Some examples:

• bisecting [0, 2] gives the intervals [0, 1] and [1, 2]

• bisecting [-1, 1] gives the intervals [-1, 0] and [0, 1]

• bisecting an arbitrary interval [a,b] gives the intervals \left[a,\frac{a+b}2\right] and \left[\frac{a+b}2,b\right]

7 0
2 years ago
A store sells small notebooks for ​$6 and large notebooks for ​$10. If a student buys 6 notebooks and spends ​$52​, how many of
NISA [10]

Answer:

you can say he bought 2 small notebooks and 4 big notebooks

Step-by-step explanation:

we have 52 dollars here

so if we have 4 large notebooks that will cost 40 dollars and if we have 2 small notebooks on addiction to that, that will cost 12 more dollars

now adding up 40 and 12 we get $52 !

3 0
3 years ago
X over 7+4 is greater than or equal to 16
Blizzard [7]

X/11>=16

X>=16x11

X>=176

5 0
3 years ago
What is the answer for (10+4)x7-45*9 ???
Viktor [21]
I got -307 (if the x stands for multiplication)
6 0
3 years ago
Read 2 more answers
A cement walkway of uniform width has been built around an in-ground rectangular pool. the area of the walkway is 1344 square fe
Elza [17]

Answer:

6 feet.

Step-by-step explanation:

Dimensions of the Pool =80 feet long by 20 feet wide

Area of the walkway =1344 square feet.

If the width of the walkway=w

  • Length of the Larger Rectangle =80+2w
  • Width of the Larger Rectangle =20+2w

Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

1344=(80+2w)(20+2w)-(80*20)\\1344=80*20+160w+40w+4w^2-80*20\\4w^2+200w=1344\\4w^2+200w-1344=0\\We factorize\\4(w^2+50w-336)=0\\4(w^2-6w+56w-336)=0\\w(w-6)+56(w-6)=0\\(w-6)(w+56)=0\\w-6=0$ or $ w+56=0\\w=6$ ft or $ w=-56$ \\Therefore, the width of the walkway , w=6 feet.

6 0
3 years ago
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