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PtichkaEL [24]
3 years ago
11

To paint a house, two painters are hired. The first painter can paint the entire house in ten hours. The second painter will nee

d six hours to paint the entire house. If the two painters start painting at 8:00 am, at what time will they finish painting the house?
Mathematics
2 answers:
Korolek [52]3 years ago
7 0
First painter can do house in 10 hours
in 1 hour, does 1/10 house

second is 6 hours
in 1 hour, does 1/6 house

if both start at same time, then how long, then add to 8:00

1st+2nd rate per hour=1/10+1/6=6/60+10/60=16/60 per hour=4/15
4/15 times x hours=1/1house
multiply both sides by 15/4 to clear fraction (15/4 times 4/15=60/60=1)
x hours=15/4=3 and 3/4 hours=3 housr and 45 mins

8:00+3 hours and 45mins=11:45

end at 11:45 AM
I have a feeling this question was asked about amont before
guajiro [1.7K]3 years ago
4 0
Simple,

take both the hours, and the beginning time they start at,

8:00 AM

For the first painter:

8:00 AM+10 hours...

Beginning at 8..

9,10,11,12,1,2,3,4,5,6

Thus, the FIRST painter will end at 6 P.M.

Now, the second painter:

8:00 AM+6 hours

Beginning at 8....

9,10,11,12,1,2

Thus, the second painter will end at 2 P.M.
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