Answer:
12.44 g
Explanation:
2C4H10 + 13O2 = 8CO2 + 10H2O
n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).
n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).
Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.
mass of CO2 produced =
M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol
M = 0.5656/2 * 44
M = 0.2828 * 44
M = 12.44 of CO2
Answer:Prophase is the first stage of mitosis. In prophase,
Explanation:
Double pressure and you get the volume.At constant temp. volume =5L
P1V1=P2V2
100 times 2=200timesV2
V2=1000/200
V2=5.0l
Protective gear, a guardian or instructor, basic safety equipment
The hydrogen will react with 12 g B
Mass of B = 3.3 g H_2 × (3.6 g B/1.0 g H_2) = 12 g B