It’s C I hope this was useful and have a great day!
<h2>
Hello!</h2>
The answer is:
The approximate volume is 9.84 L.

<h2>
Why?</h2>
Since we are given the numer of moles, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.
The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

Where,
P is the pressure of the gas.
V is the volume of the gas.
n is the number of moles of the gas.
T is the absolute temperature of the gas (Kelvin).
R is the ideal gas constant, which is equal to:

So, we are given the information:

Now, substituting the given information and isolating the Volume from The Ideal Gas Law equation, we have:




So, the approximate volume is 9.84 L.

Have a nice day!
<em>Answer:</em>
<h2>
<em>4</em><em>9</em><em>/</em><em>3</em><em>0</em></h2>
<em>Solution</em><em>,</em>
<em>Reciprocal</em><em> </em><em>of </em><em>6</em><em>/</em><em>1</em><em>1</em><em>=</em><em>1</em><em>1</em><em>/</em><em>6</em>
<em>Now,</em>
<em>-</em><em>1</em><em>/</em><em>5</em><em>+</em><em>1</em><em>1</em><em>/</em><em>6</em>
<em>=</em><em>-</em><em>1</em><em>*</em><em>6</em><em>+</em><em>1</em><em>1</em><em>*</em><em>5</em><em>/</em><em>3</em><em>0</em>
<em>=</em><em>-</em><em>6</em><em>+</em><em>5</em><em>5</em><em>/</em><em>3</em><em>0</em>
<em>=</em><em>4</em><em>9</em><em>/</em><em>3</em><em>0</em>
<em>Hope </em><em>it</em><em> helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
I believe the correct answer from the choices listed above is option A. The E+ of the cell would be 2.47 V. E of the cell is given by the formula E(cathode) - E(anode) . <span>So in this case the first half cell reaction is the reaction that takes place in the cathode and the second one takes place in the anode.</span>
Length of 1 side 1.2*10^-5km =1.2*10^-5*10^5 =1.2cm
<span>volume of the cube (1.2)^3=1.728 cm^3 </span>
<span>density= mass/volume= 1.1/1.728=0.636 g/cm^3</span>