The answer is 21 that is it
1. The magnitude of the gravitational force between the Earth and an m is 54.1 N.
2. The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
3. The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
<h3>
Gravitational force between Earth and mass, m</h3>
The gravitational force between Earth and mass, m is calculated as follows;
F(Earth) = Gm₁m₂/R²
F(Earth) = (6.67 x 10⁻¹¹ x 5.5 x 5.98 x 10²⁴)/(6,370,000)²
F(Earth) = 54.1 N
<h3>
Gravitational force between Moon and mass, m</h3>
F(moon) = Gm₁m₂/R²
F(moon) = (6.67 x 10⁻¹¹ x 5.5 x 7.36x 10²²)/(3.76 x 10⁸)²
F(moon) = 1.91 x 10⁻⁴ N
<h3>
Gravitational force between Sun and mass, m</h3>
F(sun) = Gm₁m₂/R²
F(sun) = (6.67 x 10⁻¹¹ x 5.5 x 1.99x 10³⁰)/(1.5 x 10¹¹)²
F(sun) = 0.0324 N
<h3>Ratio of F(sun) to F(moon)</h3>
= 0.0324/1.91 x 10⁻⁴
= 169.6
Thus, the magnitude of the gravitational force between the Earth and an m is 54.1 N.
The magnitude of the gravitational force between the Moon and an m is 1.91 x 10⁻⁴ N.
The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.
Learn more about gravitational force here: brainly.com/question/72250
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Answer:
Just 0.335 of the light is transmitted through the second polarizer
Explanation:
When the light passes through to the second polarizer, the intensity is equal:
![I_{2}= \frac{I}{2} cos\theta](https://tex.z-dn.net/?f=I_%7B2%7D%3D%20%5Cfrac%7BI%7D%7B2%7D%20cos%5Ctheta)
Where
θ = 48°
Replacing:
![I_{2}= \frac{I}{2} cos\48=0.335I](https://tex.z-dn.net/?f=I_%7B2%7D%3D%20%5Cfrac%7BI%7D%7B2%7D%20cos%5C48%3D0.335I)
Explanation:
Acceleration is the change in velocity over time.
a = Δv / Δt
a = (26 m/s − 9 m/s) / 8 s
a ≈ 2.1 m/s²
Answer:
Explanation:
object distance u = 38.5 cm ( negative )
focal length f = 17.5 cm ( negative )
mirror formula
1 / v + 1 / u = 1 / f
1 / v - 1 / 38.5 = - 1 / 17.5
1 / v = - 1 / 17.5 + 1 / 38.5
= - 0 .03116
v = - 1 / .03116 = - 32 cm
Image will be formed in front of the mirror at 32 cm distance .